[amp_mcq option1=”4.4 mm” option2=”5.5 mm” option3=”6.5 mm” option4=”7.5 mm” correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\text{A}}$.<\/p>\n
The displacement of the pictured position of a point of h elevation on a vertical photograph taken with a camera of 30 cm focal length, from an altitude of 3000 m, is given by the following formula:<\/p>\n
$$d = \\frac{h}{f} \\tan \\theta$$<\/p>\n
where $h$ is the elevation of the point, $f$ is the focal length of the camera, and $\\theta$ is the angle of view of the camera.<\/p>\n
In this case, $h = 3000$ m, $f = 30$ cm, and $\\theta = 60^\\circ$. Substituting these values into the formula, we get:<\/p>\n
$$d = \\frac{3000 \\text{ m}}{30 \\text{ cm}} \\tan 60^\\circ = 4.4 \\text{ mm}$$<\/p>\n
Therefore, the displacement of the pictured position of a point of h elevation on a vertical photograph taken with a camera of 30 cm focal length, from an altitude of 3000 m, is 4.4 mm.<\/p>\n
Option A is the correct answer because it is the only option that is within the range of possible values for the displacement. The other options are too large or too small.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”4.4 mm” option2=”5.5 mm” option3=”6.5 mm” option4=”7.5 mm” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[654],"tags":[],"class_list":["post-8352","post","type-post","status-publish","format-standard","hentry","category-surveying","no-featured-image-padding"],"yoast_head":"\n