{"id":7947,"date":"2024-04-15T02:52:46","date_gmt":"2024-04-15T02:52:46","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=7947"},"modified":"2024-04-15T02:52:46","modified_gmt":"2024-04-15T02:52:46","slug":"if-ruling-gradient-is-i-in-20-and-there-is-also-a-horizontal-curve-of-radius-76-m-then-the-compensated-grade-should-be-a-3-b-4-c-5-d-6","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-ruling-gradient-is-i-in-20-and-there-is-also-a-horizontal-curve-of-radius-76-m-then-the-compensated-grade-should-be-a-3-b-4-c-5-d-6\/","title":{"rendered":"If ruling gradient is I in 20 and there is also a horizontal curve of radius 76 m, then the compensated grade should be A. 3 % B. 4% C. 5 % D. 6%"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;3%&#8221; option2=&#8221;4%&#8221; option3=&#8221;5%&#8221; option4=&#8221;6%&#8221; correct=&#8221;option3&#8243;]<!--more--><\/p>\n<p>The correct answer is $\\boxed{\\text{B. 4%}}$.<\/p>\n<p>The compensated grade is the maximum allowable grade for a horizontal curve. It is calculated by taking the ruling gradient and multiplying it by a factor that depends on the radius of the curve. The factor is called the cant deficiency factor, and it is equal to $1 &#8211; \\frac{r}{200}$, where $r$ is the radius of the curve in meters.<\/p>\n<p>In this case, the radius of the curve is 76 m, so the cant deficiency factor is $1 &#8211; \\frac{76}{200} = 0.88$. The compensated grade is therefore equal to $1 \\text{ in } 20 \\times 0.88 = 4\\%$.<\/p>\n<p>The other options are incorrect because they do not take into account the radius of the curve.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;3%&#8221; option2=&#8221;4%&#8221; option3=&#8221;5%&#8221; option4=&#8221;6%&#8221; correct=&#8221;option3&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[652],"tags":[],"class_list":["post-7947","post","type-post","status-publish","format-standard","hentry","category-highway-engineering","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If ruling gradient is I in 20 and there is also a horizontal curve of radius 76 m, then the compensated grade should be A. 3 % B. 4% C. 5 % D. 6%<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-ruling-gradient-is-i-in-20-and-there-is-also-a-horizontal-curve-of-radius-76-m-then-the-compensated-grade-should-be-a-3-b-4-c-5-d-6\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If ruling gradient is I in 20 and there is also a horizontal curve of radius 76 m, then the compensated grade should be A. 3 % B. 4% C. 5 % D. 6%\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;3%&#8221; 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