[amp_mcq option1=”2.30 m” option2=”2.40 m” option3=”2.45 m” option4=”2.50 m” correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\text{B) 2.40 m}}$.<\/p>\n
The volume of the ejector chamber is given by<\/p>\n
$$V = \\pi r^2 h$$<\/p>\n
where $r$ is the radius of the chamber and $h$ is the height of the chamber. The peak sewage discharge is given by<\/p>\n
$$Q = \\frac{V}{t}$$<\/p>\n
where $t$ is the time between discharges. Substituting the expression for $V$ into the expression for $Q$, we get<\/p>\n
$$Q = \\frac{\\pi r^2 h}{t}$$<\/p>\n
We are given that $h = 2 \\text{ m}$ and $t = 10 \\text{ min} = 600 \\text{ s}$. We are also given that $Q = 0.0157 \\text{ cumec} = 157 \\text{ m}^3\/\\text{s}$. Substituting these values into the expression for $Q$, we get<\/p>\n
$$157 \\text{ m}^3\/\\text{s} = \\frac{\\pi r^2 (2 \\text{ m})}{600 \\text{ s}}$$<\/p>\n
Solving for $r$, we get<\/p>\n
$$r = \\sqrt{\\frac{157 \\text{ m}^3\/\\text{s} \\times 600 \\text{ s}}{\\pi (2 \\text{ m})^2}} = 2.40 \\text{ m}$$<\/p>\n
Therefore, the diameter of the ejector chamber is $\\boxed{\\text{2.40 m}}$.<\/p>\n
The other options are incorrect because they do not result in a diameter that is consistent with the given information.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”2.30 m” option2=”2.40 m” option3=”2.45 m” option4=”2.50 m” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[650],"tags":[],"class_list":["post-7650","post","type-post","status-publish","format-standard","hentry","category-waste-water-engineering","no-featured-image-padding"],"yoast_head":"\n