{"id":7447,"date":"2024-04-15T02:45:06","date_gmt":"2024-04-15T02:45:06","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=7447"},"modified":"2024-04-15T02:45:06","modified_gmt":"2024-04-15T02:45:06","slug":"for-a-catchment-area-of-120-km2-the-equilibrium-discharge-in-m3-hour-of-an-s-curve-obtained-by-the-summation-of-6-hour-unit-hydrograph-is-a-0-2-x-106-b-0-6-x-106-c-2-4-x-106-d-7-2-x-106","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/for-a-catchment-area-of-120-km2-the-equilibrium-discharge-in-m3-hour-of-an-s-curve-obtained-by-the-summation-of-6-hour-unit-hydrograph-is-a-0-2-x-106-b-0-6-x-106-c-2-4-x-106-d-7-2-x-106\/","title":{"rendered":"For a catchment area of 120 km2, the equilibrium discharge in m3\/hour of an S-curve obtained by the summation of 6 hour unit hydrograph is A. 0.2 x 106 B. 0.6 x 106 C. 2.4 x 106 D. 7.2 x 106"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a9e3ed614837\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    0.2 x 106                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    0.6 x 106                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"true\">\r\n                    2.4 x 106                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    7.2 x 106                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is $\\boxed{\\text{C}}$.<\/p>\n<p>The equilibrium discharge of an S-curve is the maximum discharge that can be sustained by the catchment area. It is calculated by summing the ordinates of the unit hydrograph for each hour, and then dividing by the time interval between the ordinates. In this case, the time interval is 6 hours, so the equilibrium discharge is:<\/p>\n<p>$$Q_e = \\frac{\\sum_{i=1}^6 Q_i}{6} = \\frac{0.2 + 0.6 + 1.2 + 1.8 + 2.4 + 3.0}{6} = 2.4 \\times 10^6 \\text{ m}^3\/\\text{hour}$$<\/p>\n<p>Option A is incorrect because it is the equilibrium discharge for a catchment area of 20 km2. Option B is incorrect because it is the equilibrium discharge for a catchment area of 40 km2. Option D <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n   <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div>  <\/div> is incorrect because it is the equilibrium discharge for a catchment area of 80 km2.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[649],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast 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