{"id":7393,"date":"2024-04-15T02:44:11","date_gmt":"2024-04-15T02:44:11","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=7393"},"modified":"2024-04-15T02:44:11","modified_gmt":"2024-04-15T02:44:11","slug":"if-delta-is-the-depth-of-water-in-metres-b-is-the-number-of-days-of-base-period-and-d-is-the-duty-in-hectare-cumec-the-relationship-which-holds-good-is-a-textd-delta-frac8-6","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-delta-is-the-depth-of-water-in-metres-b-is-the-number-of-days-of-base-period-and-d-is-the-duty-in-hectare-cumec-the-relationship-which-holds-good-is-a-textd-delta-frac8-6\/","title":{"rendered":"If $$\\Delta $$ is the depth of water in metres, B is the number of days of base period and D is the duty in hectare\/cumec, the relationship which holds good, is A. $${\\text{D}} = \\Delta \\frac{{8.64{\\text{D}}}}{{\\text{B}}}$$ B. $${\\text{B}} = \\Delta \\frac{{8.64{\\text{B}}}}{{\\text{D}}}$$ C. $${\\text{D}} = \\frac{{8.64\\Delta }}{{\\text{B}}}$$ D. $$\\Delta = \\frac{{8.64{\\text{B}}}}{{\\text{D}}}$$"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a9b9b1b4e083\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    $${\text{D}} = Delta \frac{{8.64{\text{D}}}}{{\text{B}}}$$                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    $${\text{B}} = Delta \frac{{8.64{\text{B}}}}{{\text{D}}}$$                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"true\">\r\n                    $${\text{D}} = \frac{{8.64Delta }}{{\text{B}}}$$                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    $$Delta = \frac{{8.64{\text{B}}}}{{\text{D}}}$$                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is $\\boxed{\\text{C}}$.<\/p>\n<p>The duty is the amount of water that can be applied to a hectare of land in one day. It is calculated by dividing the depth of water by the number of days of the base period. The base period is the time period over which the duty is calculated. It is usually taken to be one year.<\/p>\n<p>The depth of water is the vertical distance from the surface of the water to the bottom of the reservoir. It is measured in metres.<\/p>\n<p>The number of days of the base period is the number of days in the period over which the duty is calculated. It is usually taken to be one year.<\/p>\n<p>Therefore, the relationship between the depth of water, the number of days of the base period, and the duty is:<\/p>\n<p>$$\\text{D} = \\frac{{8.64\\Delta }}{{\\text{B}}}$$<\/p>\n<p>where:<\/p>\n<ul>\n<li>$\\text{D}$ is the duty in hectare\/cumec<\/li>\n<li>$\\Delta$ is the depth of water in metres<\/li>\n<li>$\\text{B}$ <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> is the number of days of the base period<\/li>\n<\/ul>\n<p>The other options are incorrect because they do not correctly represent the relationship between the depth of water, the number of days of the base period, and the duty.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[649],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If $$\\Delta $$ is the depth of water in metres, B is the number of days of base period and D is the duty in hectare\/cumec, the relationship which holds good, is A. $${\\text{D}} = \\Delta \\frac{{8.64{\\text{D}}}}{{\\text{B}}}$$ B. $${\\text{B}} = \\Delta \\frac{{8.64{\\text{B}}}}{{\\text{D}}}$$ C. $${\\text{D}} = \\frac{{8.64\\Delta }}{{\\text{B}}}$$ D. $$\\Delta = 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in hectare\/cumec, the relationship which holds good, is A. $${\\text{D}} = \\Delta \\frac{{8.64{\\text{D}}}}{{\\text{B}}}$$ B. $${\\text{B}} = \\Delta \\frac{{8.64{\\text{B}}}}{{\\text{D}}}$$ C. $${\\text{D}} = \\frac{{8.64\\Delta }}{{\\text{B}}}$$ D. $$\\Delta = \\frac{{8.64{\\text{B}}}}{{\\text{D}}}$$","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-delta-is-the-depth-of-water-in-metres-b-is-the-number-of-days-of-base-period-and-d-is-the-duty-in-hectare-cumec-the-relationship-which-holds-good-is-a-textd-delta-frac8-6\/","og_locale":"en_US","og_type":"article","og_title":"If $$\\Delta $$ is the depth of water in metres, B is the number of days of base period and D is the duty in hectare\/cumec, the relationship which holds good, is A. $${\\text{D}} = \\Delta \\frac{{8.64{\\text{D}}}}{{\\text{B}}}$$ B. $${\\text{B}} = 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