[amp_mcq option1=”1″ option2=”$$\\frac{4}{3}$$” option3=”2″ option4=”4″ correct=”option1″]<\/p>\n
The correct answer is $\\frac{4}{3}$.<\/p>\n
The momentum correction factor is a dimensionless quantity that is used to account for the fact that the velocity is not uniform across the cross-sectional area of a pipe. The momentum correction factor is defined as follows:<\/p>\n
$$f = \\frac{2}{3} \\left( 1 + \\frac{2}{3} \\frac{A_1}{A} \\right)$$<\/p>\n
where $A_1$ is the area of the half of the cross-sectional area where the velocity is zero and $A$ is the total cross-sectional area of the pipe.<\/p>\n
In this case, the velocity is zero over half of the cross-sectional area and is uniform over the remaining half. Therefore, $A_1 = \\frac{1}{2} A$ and $A = 2 A_1$. Substituting these values into the equation for the momentum correction factor, we get:<\/p>\n
$$f = \\frac{2}{3} \\left( 1 + \\frac{2}{3} \\frac{A_1}{A} \\right) = \\frac{2}{3} \\left( 1 + \\frac{2}{3} \\frac{1}{2} \\right) = \\frac{4}{3}$$<\/p>\n
Therefore, the momentum correction factor is $\\frac{4}{3}$.<\/p>\n
The other options are incorrect because they do not account for the fact that the velocity is not uniform across the cross-sectional area of the pipe.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”1″ option2=”$$\\frac{4}{3}$$” option3=”2″ option4=”4″ correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[648],"tags":[],"class_list":["post-7309","post","type-post","status-publish","format-standard","hentry","category-hydraulics-and-fluid-mechanics","no-featured-image-padding"],"yoast_head":"\n