[amp_mcq option1=”1000 kg” option2=”4000 kg” option3=”2000 kg” option4=”2500 kg” correct=”option1″]<\/p>\n
The correct answer is $\\boxed{\\text{C}}$.<\/p>\n
The pressure at a depth of $h$ below the free surface of water is given by the equation $P = \\rho g h$, where $\\rho$ is the density of water and $g$ is the acceleration due to gravity. The density of water is approximately $1000 \\frac{kg}{m^3}$ and the acceleration due to gravity is approximately $9.8 \\frac{m}{s^2}$. Therefore, the pressure on a 1m \u00c3\u0097 1m gate immersed vertically at a depth of 2 m below the free water surface is $P = (1000 \\frac{kg}{m^3})(9.8 \\frac{m}{s^2})(2 m) = 19600 \\frac{N}{m^2}$. This is equivalent to a force of $19600 \\frac{N}{m^2} \\times 1 m \\times 1 m = 19600 N$ on the gate.<\/p>\n
Option A is incorrect because it is the weight of the gate. The weight of the gate is given by the equation $W = mg$, where $m$ is the mass of the gate and $g$ is the acceleration due to gravity. The mass of the gate is given by the equation $m = \\rho V$, where $\\rho$ is the density of the gate and $V$ is the volume of the gate. The density of the gate is approximately $2700 \\frac{kg}{m^3}$ and the volume of the gate is given by the equation $V = LWH$, where $L$ is the length of the gate, $W$ is the width of the gate, and $H$ is the height of the gate. The length, width, and height of the gate are not given, so the weight of the gate cannot be calculated.<\/p>\n
Option B is incorrect because it is the pressure at a depth of 1 m below the free water surface. The pressure at a depth of 1 m below the free water surface is given by the equation $P = \\rho g h = (1000 \\frac{kg}{m^3})(9.8 \\frac{m}{s^2})(1 m) = 9800 \\frac{N}{m^2}$.<\/p>\n
Option D is incorrect because it is the pressure at a depth of 2 m below the free water surface times 2. The pressure at a depth of 2 m below the free water surface is given by the equation $P = \\rho g h = (1000 \\frac{kg}{m^3})(9.8 \\frac{m}{s^2})(2 m) = 19600 \\frac{N}{m^2}$. Therefore, the pressure at a depth of 2 m below the free water surface times 2 is $19600 \\frac{N}{m^2} \\times 2 = 39200 \\frac{N}{m^2}$.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”1000 kg” option2=”4000 kg” option3=”2000 kg” option4=”2500 kg” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[648],"tags":[],"class_list":["post-7303","post","type-post","status-publish","format-standard","hentry","category-hydraulics-and-fluid-mechanics","no-featured-image-padding"],"yoast_head":"\n