[amp_mcq option1=”Less than 1 m\/sec” option2=”1 m\/sec” option3=”1.5 m\/sec” option4=”2 m\/sec” correct=”option1″]<\/p>\n
The correct answer is: A. Less than 1 m\/sec<\/p>\n
The maximum velocity for laminar flow is given by the Hagen-Poiseuille equation:<\/p>\n
$$v_max = \\frac{8Q}{\\pi r^4 \\mu}$$<\/p>\n
where $Q$ is the volumetric flow rate, $r$ is the radius of the pipe, and $\\mu$ is the dynamic viscosity of the fluid.<\/p>\n
In this case, we have $Q = 1 \\text{ m}^3\/\\text{s}$, $r = 4 \\text{ cm} = 0.04 \\text{ m}$, and $\\mu = 0.4 \\text{ cm}^2\/\\text{s}$. Substituting these values into the Hagen-Poiseuille equation, we get:<\/p>\n
$$v_max = \\frac{8 \\cdot 1}{\\pi \\cdot 0.04^4 \\cdot 0.4} = 0.072 \\text{ m\/s} = 7.2 \\text{ cm\/s}$$<\/p>\n
Therefore, the maximum velocity for laminar flow is less than 1 m\/sec.<\/p>\n
The other options are incorrect because they are greater than 1 m\/sec.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”Less than 1 m\/sec” option2=”1 m\/sec” option3=”1.5 m\/sec” option4=”2 m\/sec” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[648],"tags":[],"class_list":["post-7244","post","type-post","status-publish","format-standard","hentry","category-hydraulics-and-fluid-mechanics","no-featured-image-padding"],"yoast_head":"\n