[amp_mcq option1=”10 m\/sec” option2=”25 m\/sec” option3=”2 m\/sec” option4=”50 m\/sec” correct=”option3″]<\/p>\n
The correct answer is C. 2 m\/sec.<\/p>\n
The Froude number is a dimensionless number that is used to compare the flow of fluids around two objects of different sizes. It is defined as:<\/p>\n
$Fr = \\frac{v}{\\sqrt{gL}}$<\/p>\n
where $v$ is the velocity of the object, $g$ is the acceleration due to gravity, and $L$ is a characteristic length of the object.<\/p>\n
For dynamic similarity, the Froude numbers of the ship and the model must be equal. Therefore, the velocity of the model must be:<\/p>\n
$v_m = \\sqrt{\\frac{g_m L_m}{g_L L_L}} v_L$<\/p>\n
where $g_m$ and $g_L$ are the accelerations due to gravity at the model and ship locations, respectively, and $L_m$ and $L_L$ are the characteristic lengths of the model and ship, respectively.<\/p>\n
In this case, $g_m = g_L$ and $L_m = \\frac{1}{25} L_L$. Therefore, the velocity of the model is:<\/p>\n
$v_m = \\sqrt{\\frac{g_L L_L}{25 g_L L_L}} v_L = \\frac{1}{5} v_L = 2 \\text{ m\/sec}$<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”10 m\/sec” option2=”25 m\/sec” option3=”2 m\/sec” option4=”50 m\/sec” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[648],"tags":[],"class_list":["post-7192","post","type-post","status-publish","format-standard","hentry","category-hydraulics-and-fluid-mechanics","no-featured-image-padding"],"yoast_head":"\n