[amp_mcq option1=”The extreme point of the oscillation” option2=”Through the mean position” option3=”Through a point at half amplitude” option4=”None of these” correct=”option1″]<\/p>\n
The correct answer is: A. The extreme point of the oscillation.<\/p>\n
A particle moving with a simple harmonic motion attains its maximum velocity when it passes through the extreme point of the oscillation. This is because the velocity of the particle is given by the equation $v = -\\omega A \\sin \\omega t$, where $\\omega$ is the angular frequency of the oscillation, $A$ is the amplitude of the oscillation, and $t$ is the time. The maximum value of the sine function is 1, so the maximum velocity of the particle occurs when $\\sin \\omega t = 1$. This happens when $t = \\frac{\\pi}{2} + 2 \\pi n$, where $n$ is an integer. Therefore, the maximum velocity of the particle occurs when it passes through the extreme point of the oscillation.<\/p>\n
The other options are incorrect because:<\/p>\n
[amp_mcq option1=”The extreme point of the oscillation” option2=”Through the mean position” option3=”Through a point at half amplitude” option4=”None of these” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[645],"tags":[],"class_list":["post-6894","post","type-post","status-publish","format-standard","hentry","category-applied-mechanics-and-graphic-statics","no-featured-image-padding"],"yoast_head":"\n