[amp_mcq option1=”60 N” option2=”80 N” option3=”100 N” option4=”120 N” correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\text{B) 80 N}}$.<\/p>\n
To solve this problem, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. In this case, the hypotenuse is the force of 130 N, and the other two sides are the forces P and Q. So, we have the equation:<\/p>\n
$130^2 = P^2 + Q^2$<\/p>\n
$16900 = 2500 + Q^2$<\/p>\n
$Q^2 = 14400$<\/p>\n
$Q = \\sqrt{14400}$<\/p>\n
$Q = 80$<\/p>\n
Therefore, the magnitude of Q is 80 N.<\/p>\n
Option A is incorrect because 60 N is not a solution to the equation $130^2 = P^2 + Q^2$.<\/p>\n
Option C is incorrect because 100 N is not a solution to the equation $130^2 = P^2 + Q^2$.<\/p>\n
Option D is incorrect because 120 N is not a solution to the equation $130^2 = P^2 + Q^2$.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”60 N” option2=”80 N” option3=”100 N” option4=”120 N” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[645],"tags":[],"class_list":["post-6810","post","type-post","status-publish","format-standard","hentry","category-applied-mechanics-and-graphic-statics","no-featured-image-padding"],"yoast_head":"\n