{"id":6807,"date":"2024-04-15T02:34:28","date_gmt":"2024-04-15T02:34:28","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=6807"},"modified":"2024-04-15T02:34:28","modified_gmt":"2024-04-15T02:34:28","slug":"a-block-of-weight-50-kg-is-placed-on-a-horizontal-plane-when-a-horizontal-force-of-18-kg-is-applied-the-block-is-just-on-the-point-of-motion-the-angle-of-friction-is-a-17a-48-b-18a","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-block-of-weight-50-kg-is-placed-on-a-horizontal-plane-when-a-horizontal-force-of-18-kg-is-applied-the-block-is-just-on-the-point-of-motion-the-angle-of-friction-is-a-17a-48-b-18a\/","title":{"rendered":"A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. The angle of friction is A. 17\u00c2\u00b0 48&#8242; B. 18\u00c2\u00b0 48&#8242; C. 19\u00c2\u00b0 48&#8242; D. 20\u00c2\u00b0 48&#8242;"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6ab2a0a9861bd\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"true\">\r\n                    17\u00c2\u00b0 48&#039;                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    18\u00c2\u00b0 48&#039;                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    19\u00c2\u00b0 48&#039;                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    20\u00c2\u00b0 48&#039;                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is $\\boxed{\\text{B) 18\u00c2\u00b0 48&#8242;}}$.<\/p>\n<p>The angle of friction is the angle between the applied force and the normal force, when the block is just on the point of motion. The normal force is the force that the surface exerts on the <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n          <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div>       <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> block, perpendicular to the surface. The applied force is the force that we apply to the block, in the direction of motion.<\/p>\n<p>The angle of friction can be calculated using the following formula:<\/p>\n<p>$$\\mu = \\tan \\theta$$<\/p>\n<p>where $\\mu$ is the coefficient of friction and $\\theta$ is the angle of friction.<\/p>\n<p>The coefficient of friction is a constant that depends on the materials of the block and the surface. It can be found in tables or determined experimentally.<\/p>\n<p>In this case, the weight of the block is 50 kg. The normal force is equal to the weight of the block, which is 500 N. The applied force is 18 kg, which is 180 N.<\/p>\n<p>The coefficient of friction is given by:<\/p>\n<p>$$\\mu = \\frac{180}{500} = 0.36$$<\/p>\n<p>The angle of friction is given by:<\/p>\n<p>$$\\theta = \\arctan \\mu = 18\u00c2\u00b0 48&#8217;$$<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[645],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. The angle of friction is A. 17\u00c2\u00b0 48&#039; B. 18\u00c2\u00b0 48&#039; C. 19\u00c2\u00b0 48&#039; D. 20\u00c2\u00b0 48&#039;<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-block-of-weight-50-kg-is-placed-on-a-horizontal-plane-when-a-horizontal-force-of-18-kg-is-applied-the-block-is-just-on-the-point-of-motion-the-angle-of-friction-is-a-17a-48-b-18a\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A block of weight 50 kg is placed on a horizontal plane. When a horizontal force of 18 kg is applied, the block is just on the point of motion. 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