[amp_mcq option1=”188.5 m\/sec” option2=”18.85 m\/sec” option3=”1.885 m\/sec” option4=”0.18845 m\/sec” correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\text{C}}$.<\/p>\n
The maximum velocity of a body vibrating with a simple harmonic motion of amplitude $A$ and frequency $f$ is given by:<\/p>\n
$$v_{max} = \\omega A$$<\/p>\n
where $\\omega = 2\\pi f$ is the angular frequency.<\/p>\n
In this case, we have $A = 150 \\text{ mm} = 0.15 \\text{ m}$ and $f = 2 \\text{ vibrations\/sec} = 2 \\pi \\text{ rad\/sec}$. Substituting these values into the equation for $v_{max}$, we get:<\/p>\n
$$v_{max} = 2\\pi (2 \\pi) (0.15 \\text{ m}) = 1.885 \\text{ m\/sec}$$<\/p>\n
Option A is incorrect because it is too large. Option B is incorrect because it is too small. Option D is incorrect because it is much too small.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”188.5 m\/sec” option2=”18.85 m\/sec” option3=”1.885 m\/sec” option4=”0.18845 m\/sec” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[645],"tags":[],"class_list":["post-6782","post","type-post","status-publish","format-standard","hentry","category-applied-mechanics-and-graphic-statics","no-featured-image-padding"],"yoast_head":"\n