[amp_mcq option1=”$$\\frac{1}{2}$$” option2=”$$\\frac{3}{2}$$” option3=”2″ option4=”3″ correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\frac{3}{2}}$.<\/p>\n
The angular acceleration is given by $\\alpha = \\frac{F}{I}$, where $F$ is the tangential force and $I$ is the moment of inertia. In this case, $F = 5 \\text{ N}$ and $I = 20 \\text{ kg.m}^2$, so $\\alpha = \\frac{5 \\text{ N}}{20 \\text{ kg.m}^2} = \\frac{1}{4} \\text{ rad\/s}^2$.<\/p>\n
The angular velocity is given by $\\omega = \\omega_0 + \\alpha t$, where $\\omega_0$ is the initial angular velocity and $t$ is the time. In this case, $\\omega_0 = 0$, so $\\omega = \\frac{1}{4} \\text{ rad\/s}^2 \\times 3 \\text{ s} = \\frac{3}{2} \\text{ rad\/s}$.<\/p>\n
Therefore, the increase in angular velocity in radian per second is $\\boxed{\\frac{3}{2}}$.<\/p>\n
Here is a brief explanation of each option:<\/p>\n
[amp_mcq option1=”$$\\frac{1}{2}$$” option2=”$$\\frac{3}{2}$$” option3=”2″ option4=”3″ correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[645],"tags":[],"class_list":["post-6781","post","type-post","status-publish","format-standard","hentry","category-applied-mechanics-and-graphic-statics","no-featured-image-padding"],"yoast_head":"\n