{"id":6771,"date":"2024-04-15T02:33:56","date_gmt":"2024-04-15T02:33:56","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=6771"},"modified":"2024-04-15T02:33:56","modified_gmt":"2024-04-15T02:33:56","slug":"for-lifting-a-load-of-50-kg-through-a-distance-of-2-5-cm-an-effort-of-12-5-kg-is-moved-through-a-distance-of-40-cm-the-efficiency-of-the-lifting-machine-is-a-60-b-65-c-70-d-75","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/for-lifting-a-load-of-50-kg-through-a-distance-of-2-5-cm-an-effort-of-12-5-kg-is-moved-through-a-distance-of-40-cm-the-efficiency-of-the-lifting-machine-is-a-60-b-65-c-70-d-75\/","title":{"rendered":"For lifting a load of 50 kg through a distance of 2.5 cm, an effort of 12.5 kg is moved through a distance of 40 cm. The efficiency of the lifting machine, is A. 60 % B. 65 % C. 70 % D. 75 %"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;60%&#8221; option2=&#8221;65%&#8221; option3=&#8221;70%&#8221; option4=&#8221;75%&#8221; correct=&#8221;option3&#8243;]<!--more--><\/p>\n<p>The correct answer is $\\boxed{\\text{B. 65\\%}}$.<\/p>\n<p>The efficiency of a machine is the ratio of the work output to the work input. In this case, the work output is the lifting of a load of 50 kg through a distance of 2.5 cm, which is $50 \\times 0.025 = 1.25 \\text{ J}$. The work input is the effort of 12.5 kg moved through a distance of 40 cm, which is $12.5 \\times 0.4 = 5 \\text{ J}$. Therefore, the efficiency of the machine is $\\frac{1.25}{5} = 0.25 = 65\\%$.<\/p>\n<p>Option A is incorrect because it is the efficiency of a machine that lifts a load of 50 kg through a distance of 5 cm, not 2.5 cm. Option C is incorrect because it is the efficiency of a machine that lifts a load of 50 kg through a distance of 1 cm, not 2.5 cm. Option D is incorrect because it is the efficiency of a machine that lifts a load of 50 kg through a distance of 0.5 cm, not 2.5 cm.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;60%&#8221; option2=&#8221;65%&#8221; option3=&#8221;70%&#8221; option4=&#8221;75%&#8221; correct=&#8221;option3&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[645],"tags":[],"class_list":["post-6771","post","type-post","status-publish","format-standard","hentry","category-applied-mechanics-and-graphic-statics","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>For lifting a load of 50 kg through a distance of 2.5 cm, an effort of 12.5 kg is moved through a distance of 40 cm. The efficiency of the lifting machine, is A. 60 % B. 65 % C. 70 % D. 75 %<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/for-lifting-a-load-of-50-kg-through-a-distance-of-2-5-cm-an-effort-of-12-5-kg-is-moved-through-a-distance-of-40-cm-the-efficiency-of-the-lifting-machine-is-a-60-b-65-c-70-d-75\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"For lifting a load of 50 kg through a distance of 2.5 cm, an effort of 12.5 kg is moved through a distance of 40 cm. 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