{"id":6680,"date":"2024-04-15T02:32:32","date_gmt":"2024-04-15T02:32:32","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=6680"},"modified":"2024-04-15T02:32:32","modified_gmt":"2024-04-15T02:32:32","slug":"minimum-pull-in-a-suspended-cable-with-supports-at-two-ends-is-equal-to-a-horizontal-thrust-b-support-reactions-c-resultant-of-horizontal-thrust-and-support-reaction-d-half-the-weight-of-the-cable","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/minimum-pull-in-a-suspended-cable-with-supports-at-two-ends-is-equal-to-a-horizontal-thrust-b-support-reactions-c-resultant-of-horizontal-thrust-and-support-reaction-d-half-the-weight-of-the-cable\/","title":{"rendered":"Minimum pull in a suspended cable with supports at two ends is equal to A. Horizontal thrust B. Support reactions C. Resultant of horizontal thrust and support reaction D. Half the weight of the cable"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a991cb3cc95b\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    Horizontal thrust                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    Support reactions                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    Resultant of horizontal thrust and support reaction                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"true\">\r\n                    Half the weight of the cable                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: <strong>D. Half the weight of the cable<\/strong>.<\/p>\n<p>A suspended cable with supports at two ends is in equilibrium under the action of <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> its own weight and the two support reactions. The support reactions are equal in magnitude and opposite in direction, and they act at the points of support. The weight of the cable acts vertically downwards through its center of mass.<\/p>\n<p>The minimum pull in the cable is the resultant of the two support reactions and the weight of the cable. The resultant is a vertical force that acts through the center <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> of mass of the cable. The magnitude of the resultant is equal to half the weight of the cable.<\/p>\n<p>Option A: Horizontal thrust is not a force that acts on a suspended cable.<\/p>\n<p>Option B: Support reactions are the forces that the supports exert on the cable. They are equal in magnitude and opposite in direction.<\/p>\n<p>Option C: The resultant of the horizontal thrust and the support reaction is a vertical force that acts through the center of mass of the cable. The magnitude of the resultant is equal to half the weight of the cable.<\/p>\n<p>Option D: Half the weight of the cable is the magnitude of the resultant of the two support reactions and the weight of the cable.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[645],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Minimum pull in a suspended cable with supports at two ends is equal to A. Horizontal thrust B. Support reactions C. Resultant of horizontal thrust and support reaction D. 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