{"id":6036,"date":"2024-04-15T02:22:55","date_gmt":"2024-04-15T02:22:55","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=6036"},"modified":"2024-04-15T02:22:55","modified_gmt":"2024-04-15T02:22:55","slug":"in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/","title":{"rendered":"In case of plastic design, the calculated maximum shear capacity of a beam as per IS : 800 shall be (where, Aw = effective cross-sectional area resisting shear, fy = yield stress of the steel) A. 0.55 Aw fy B. 0.65 Aw fy C. 0.75 Aw fy D. 0.85 Aw fy"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;0.55 Aw fy&#8221; option2=&#8221;0.65 Aw fy&#8221; option3=&#8221;0.75 Aw fy&#8221; option4=&#8221;0.85 Aw fy&#8221; correct=&#8221;option4&#8243;]<!--more--><\/p>\n<p>The correct answer is: D. 0.85 Aw fy<\/p>\n<p>The maximum shear capacity of a beam as per IS : 800 is given by the following equation:<\/p>\n<p>$V_{max} = 0.85Awfy$<\/p>\n<p>where:<\/p>\n<ul>\n<li>$V_{max}$ is the maximum shear capacity of the beam<\/li>\n<li>$Aw$ is the effective cross-sectional area resisting shear<\/li>\n<li>$fy$ is the yield stress of the steel<\/li>\n<\/ul>\n<p>The value of 0.85 is a factor of safety that is used to account for the uncertainty in the material properties and the loading conditions.<\/p>\n<p>The other options are incorrect because they do not take into account the factor of safety.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;0.55 Aw fy&#8221; option2=&#8221;0.65 Aw fy&#8221; option3=&#8221;0.75 Aw fy&#8221; option4=&#8221;0.85 Aw fy&#8221; correct=&#8221;option4&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[642],"tags":[],"class_list":["post-6036","post","type-post","status-publish","format-standard","hentry","category-design-of-steel-structures","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>In case of plastic design, the calculated maximum shear capacity of a beam as per IS : 800 shall be (where, Aw = effective cross-sectional area resisting shear, fy = yield stress of the steel) A. 0.55 Aw fy B. 0.65 Aw fy C. 0.75 Aw fy D. 0.85 Aw fy<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"In case of plastic design, the calculated maximum shear capacity of a beam as per IS : 800 shall be (where, Aw = effective cross-sectional area resisting shear, fy = yield stress of the steel) A. 0.55 Aw fy B. 0.65 Aw fy C. 0.75 Aw fy D. 0.85 Aw fy\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;0.55 Aw fy&#8221; option2=&#8221;0.65 Aw fy&#8221; option3=&#8221;0.75 Aw fy&#8221; option4=&#8221;0.85 Aw fy&#8221; correct=&#8221;option4&#8243;]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2024-04-15T02:22:55+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"In case of plastic design, the calculated maximum shear capacity of a beam as per IS : 800 shall be (where, Aw = effective cross-sectional area resisting shear, fy = yield stress of the steel) A. 0.55 Aw fy B. 0.65 Aw fy C. 0.75 Aw fy D. 0.85 Aw fy","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/","og_locale":"en_US","og_type":"article","og_title":"In case of plastic design, the calculated maximum shear capacity of a beam as per IS : 800 shall be (where, Aw = effective cross-sectional area resisting shear, fy = yield stress of the steel) A. 0.55 Aw fy B. 0.65 Aw fy C. 0.75 Aw fy D. 0.85 Aw fy","og_description":"[amp_mcq option1=&#8221;0.55 Aw fy&#8221; option2=&#8221;0.65 Aw fy&#8221; option3=&#8221;0.75 Aw fy&#8221; option4=&#8221;0.85 Aw fy&#8221; correct=&#8221;option4&#8243;]","og_url":"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2024-04-15T02:22:55+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/","url":"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/","name":"In case of plastic design, the calculated maximum shear capacity of a beam as per IS : 800 shall be (where, Aw = effective cross-sectional area resisting shear, fy = yield stress of the steel) A. 0.55 Aw fy B. 0.65 Aw fy C. 0.75 Aw fy D. 0.85 Aw fy","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2024-04-15T02:22:55+00:00","dateModified":"2024-04-15T02:22:55+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/in-case-of-plastic-design-the-calculated-maximum-shear-capacity-of-a-beam-as-per-is-800-shall-be-where-aw-effective-cross-sectional-area-resisting-shear-fy-yield-stress-of-the-steel-a-0-55\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"mcq","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/"},{"@type":"ListItem","position":3,"name":"Civil engineering","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/civil-engineering\/"},{"@type":"ListItem","position":4,"name":"Design of steel structures","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/civil-engineering\/design-of-steel-structures\/"},{"@type":"ListItem","position":5,"name":"In case of plastic design, the calculated maximum shear capacity of a beam as per IS : 800 shall be (where, Aw = effective cross-sectional area resisting shear, fy = yield stress of the steel) A. 0.55 Aw fy B. 0.65 Aw fy C. 0.75 Aw fy D. 0.85 Aw fy"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/761a7274f9cce048fa5b921221e7934820d74514df93ef195a9d22af0c1c9001?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/6036","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=6036"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/6036\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=6036"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=6036"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=6036"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}