{"id":6017,"date":"2024-04-15T02:22:38","date_gmt":"2024-04-15T02:22:38","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=6017"},"modified":"2024-04-15T02:22:38","modified_gmt":"2024-04-15T02:22:38","slug":"for-a-compression-member-with-double-angle-section-which-of-the-following-section-will-give-larger-value-of-minimum-radius-of-gyration-a-equal-angles-back-to-back-b-unqual-legged-angles-with-long","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/for-a-compression-member-with-double-angle-section-which-of-the-following-section-will-give-larger-value-of-minimum-radius-of-gyration-a-equal-angles-back-to-back-b-unqual-legged-angles-with-long\/","title":{"rendered":"For a compression member with double angle section, which of the following section will give larger value of minimum radius of gyration? A. Equal angles back to back B. Unqual legged angles with long legs back to back C. Unequal legged angles with short legs back to back D. Both (B) or (C)"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a985e46dc8b7\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"true\">\r\n                    Equal angles back to back                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    Unqual legged angles with long legs back to back                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    Unequal legged angles with short legs back to back                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    Both (B) or (C)                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: A. Equal angles back to back.<\/p>\n<p>The radius of gyration is a measure of how far the mass of an object is concentrated from its center of mass. A larger radius of gyration indicates that the mass of the object is more concentrated near its center of mass, and a smaller radius of gyration indicates that the mass of the object is more spread out.<\/p>\n<p>In a double angle section, the two angles are back to back, with their legs perpendicular to each other. The minimum radius of gyration is the radius of gyration about the axis that passes through the centers of the two angles.<\/p>\n<p>For equal angles back to back, the minimum radius of gyration is given <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> by:<\/p>\n<p>$r_g = \\frac{2}{3} \\frac{d}{2}$<\/p>\n<p>where $d$ is the distance between the centers of the two angles.<\/p>\n<p>For unequal legged <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> angles with long legs back to back, the minimum radius of gyration is given by:<\/p>\n<p>$r_g = \\frac{2}{3} \\frac{d}{2} \\sqrt{\\frac{1}{2} + \\frac{b^2}{a^2}}$<\/p>\n<p>where $a$ is the length of the long leg and $b$ is the length of the short leg.<\/p>\n<p>For unequal legged angles with short legs back to back, the minimum radius of gyration is given by:<\/p>\n<p>$r_g = \\frac{2}{3} \\frac{d}{2} \\sqrt{\\frac{1}{2} + \\frac{a^2}{b^2}}$<\/p>\n<p>As you can see, the minimum radius of gyration is always larger for equal angles back to back than it is for unequal legged angles with either the long legs or the short legs back to back. This is because the mass of the object is more concentrated near the center of mass for equal angles back to back than it is for unequal legged angles.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[642],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>For a compression member with double angle section, which of the following section will give larger value of minimum radius of gyration? A. Equal angles back to back B. Unqual legged angles with long legs back to back C. Unequal legged angles with short legs back to back D. 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