{"id":5971,"date":"2024-04-15T02:21:53","date_gmt":"2024-04-15T02:21:53","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=5971"},"modified":"2024-04-15T02:21:53","modified_gmt":"2024-04-15T02:21:53","slug":"examine-the-following-statements-i-factor-of-safety-for-steel-should-be-based-on-its-yield-stress-ii-factor-of-safety-for-steel-should-be-based-on-its-ultimate-stress-iii-factor-of-safety-for-c","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/examine-the-following-statements-i-factor-of-safety-for-steel-should-be-based-on-its-yield-stress-ii-factor-of-safety-for-steel-should-be-based-on-its-ultimate-stress-iii-factor-of-safety-for-c\/","title":{"rendered":"Examine the following statements : i) Factor of safety for steel should be based on its yield stress, ii) Factor of safety for steel should be based on its ultimate stress, iii) Factor of safety for concrete should be based on its yield stress, iv) Factor of safety for concrete should be based on its ultimate stress. The correct statements are A. (i) and (iii) B. (i) and (iv) C. (ii) and (iii) D. (ii) and (iv)"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a98c8a4d06a8\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"true\">\r\n                    (i) and (iii)                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    (i) and (iv)                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    (ii) and (iii)                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    (ii) and (iv)                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is A. (i) and (iii).<\/p>\n<p>A factor of safety is a number greater than 1 that is used to design structures and machines to account for uncertainties in the loading, material properties, and manufacturing processes. The factor of safety is typically chosen based on the consequences of failure. For example, a structure that supports human life would have a higher factor of safety than a structure that does not.<\/p>\n<p>The yield stress of a material is the stress at which it begins to deform plastically. The ultimate stress of a material is the maximum stress that it can withstand before it fails.<\/p>\n<p>For steel, the yield stress is typically lower than the ultimate stress. Therefore, the factor of safety for steel should be based on its yield stress. This will ensure that the steel does not deform plastically under normal loads.<\/p>\n<p>For concrete, the ultimate stress is typically higher than the yield stress. Therefore, the factor of safety for concrete should be based on its ultimate stress. This will ensure that the concrete does not fail under normal loads.<\/p>\n<p>Statements (i) and (iii) are correct because they state that the factor of safety for steel should be based on its yield stress and the factor of safety for concrete should be based on its ultimate stress. Statements (ii) and (iv) are incorrect because they state that the factor of safety for steel should be based on <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n          <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div>   <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> its ultimate stress and the factor of safety for concrete should be based on its yield stress.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[641],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Examine the following statements : i) Factor of safety for steel should be based on its yield stress, ii) Factor of safety for steel should be based on its ultimate stress, iii) Factor of safety for concrete should be based on its yield stress, iv) Factor of safety for concrete should be based on its ultimate stress. 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