{"id":5936,"date":"2024-04-15T02:21:19","date_gmt":"2024-04-15T02:21:19","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=5936"},"modified":"2024-04-15T02:21:19","modified_gmt":"2024-04-15T02:21:19","slug":"the-relation-between-modulus-of-rupture-fcr-splitting-strength-fcs-and-direct-tensile-strength-fcl-is-given-by-a-fcr-fcs-fcl-b-fcr-fcs-fcl-c-fcr-fcs-fcl-d-fcs-fcr-fcl","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-relation-between-modulus-of-rupture-fcr-splitting-strength-fcs-and-direct-tensile-strength-fcl-is-given-by-a-fcr-fcs-fcl-b-fcr-fcs-fcl-c-fcr-fcs-fcl-d-fcs-fcr-fcl\/","title":{"rendered":"The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by A. fcr &#8211; fcs = fcl B. fcr > fcs > fcl C. fcr < fcs < fcl D. fcs > fcr > fcl"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a9af47fb4a62\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    &#8221;fcr                <\/div>\r\n                                                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    &#8221;fcr                <\/div>\r\n                                                                                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    &#8221;fcr                <\/div>\r\n                                                                                                                                                                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: <strong>B. fcr &gt; fcs &gt; fcl<\/strong><\/p>\n<p>Modulus of rupture (fcr) is the maximum bending stress <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> that a material can withstand before it fails. Splitting strength (fcs) is the maximum tensile stress that a material can withstand before it fails when subjected to a splitting force. Direct tensile strength (fcl) is the maximum tensile stress that a material can withstand before it fails when subjected to a direct tensile force.<\/p>\n<p>In general, fcr &gt; fcs &gt; fcl. This is because the material is more likely to fail in tension than in compression. When a material is subjected to a bending force, the outer fibers of the material are in tension, while the inner fibers are in compression. The material is more likely to fail in tension, so the modulus of rupture is typically greater than the splitting strength.<\/p>\n<p>The direct tensile strength is typically the lowest of the three values, because the material is subjected to a pure tensile force. This means that <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> there is no compressive force to help support the material, so it is more likely to fail.<\/p>\n<p>It is important to note that these are just general trends, and the actual values for fcr, fcs, and fcl will vary depending on the material.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[641],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - 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