[amp_mcq option1=”The big size of the inductor” option2=”The reactance of the inductor” option3=”The current flowing in the inductor” option4=”The statement given is false” correct=”option4″]<\/p>\n
The correct answer is D. The statement given is false.<\/p>\n
A pure inductor does not consume power. The power consumed by an inductor is given by the following equation:<\/p>\n
$P = I^2R$<\/p>\n
where $I$ is the current flowing through the inductor and $R$ is the resistance of the inductor.<\/p>\n
If the inductor is pure, then $R = 0$ and therefore $P = 0$. This means that a pure inductor does not consume power.<\/p>\n
The other options are incorrect because they all suggest that the inductor consumes power. Option A suggests that the big size of the inductor is responsible for the power consumption. However, the size of the inductor does not affect the power consumption. Option B suggests that the reactance of the inductor is responsible for the power consumption. However, the reactance of the inductor only causes the current to lag behind the voltage, and it does not cause the inductor to consume power. Option C suggests that the current flowing in the inductor is responsible for the power consumption. However, the current flowing in the inductor is only a consequence of the voltage applied to the inductor, and it does not cause the inductor to consume power.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”The big size of the inductor” option2=”The reactance of the inductor” option3=”The current flowing in the inductor” option4=”The statement given is false” correct=”option4″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[739],"tags":[],"class_list":["post-58855","post","type-post","status-publish","format-standard","hentry","category-a-c-fundamentals-circuits-and-circuit-theory","no-featured-image-padding"],"yoast_head":"\n