{"id":5869,"date":"2024-04-15T02:20:10","date_gmt":"2024-04-15T02:20:10","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=5869"},"modified":"2024-04-15T02:20:10","modified_gmt":"2024-04-15T02:20:10","slug":"with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/","title":{"rendered":"With usual notations the depth of the neutral axis of a balanced section, is given by A. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} &#8211; {\\text{n}}}}{{\\text{n}}}$$ B. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{\\text{n}}}{{{\\text{d}} &#8211; {\\text{n}}}}$$ C. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{{\\text{d}} + {\\text{n}}}}{{\\text{n}}}$$ D. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{\\text{n}}}{{{\\text{d}} &#8211; {\\text{n}}}}$$"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;$$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} &#8211; {\\text{n}}}}{{\\text{n}}}$$&#8221; option2=&#8221;$$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{\\text{n}}}{{{\\text{d}} &#8211; {\\text{n}}}}$$&#8221; option3=&#8221;$$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{{\\text{d}} + {\\text{n}}}}{{\\text{n}}}$$&#8221; option4=&#8221;$$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{\\text{n}}}{{{\\text{d}} &#8211; {\\text{n}}}}$$&#8221; correct=&#8221;option1&#8243;]<!--more--><\/p>\n<p>The correct answer is: $\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} &#8211; {\\text{n}}}}{{\\text{n}}}$<\/p>\n<p>The neutral axis is an imaginary line in a beam where the strain is zero. The depth of the neutral axis is the distance from the top or bottom of the beam to the neutral axis.<\/p>\n<p>The formula for the depth of the neutral axis of a balanced section is:<\/p>\n<p>$$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} &#8211; {\\text{n}}}}{{\\text{n}}}$$<\/p>\n<p>where:<\/p>\n<ul>\n<li>$m$ is the bending moment<\/li>\n<li>$c$ is the distance from the neutral axis to the extreme fiber in tension<\/li>\n<li>$t$ is the thickness of the beam<\/li>\n<li>$d$ is the depth of the beam<\/li>\n<li>$n$ is the modulus of elasticity<\/li>\n<\/ul>\n<p>The modulus of elasticity is a measure of how much a material stretches or deforms under stress. The higher the modulus of elasticity, the less the material will deform.<\/p>\n<p>The depth of the neutral axis is important because it determines the maximum stress in the beam. The maximum stress occurs at the extreme fibers, which are the fibers farthest from the neutral axis. The stress in the beam is proportional to the distance from the neutral axis. Therefore, the fibers farthest from the neutral axis will experience the greatest stress.<\/p>\n<p>The depth of the neutral axis also affects the deflection of the beam. The deflection of the beam is the amount that the beam bends under load. The deflection of the beam is proportional to the square of the distance from the neutral axis. Therefore, the fibers farthest from the neutral axis will experience the greatest deflection.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;$$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} &#8211; {\\text{n}}}}{{\\text{n}}}$$&#8221; option2=&#8221;$$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{\\text{n}}}{{{\\text{d}} &#8211; {\\text{n}}}}$$&#8221; option3=&#8221;$$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{{\\text{d}} + {\\text{n}}}}{{\\text{n}}}$$&#8221; option4=&#8221;$$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{\\text{n}}}{{{\\text{d}} &#8211; {\\text{n}}}}$$&#8221; correct=&#8221;option1&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[640],"tags":[],"class_list":["post-5869","post","type-post","status-publish","format-standard","hentry","category-rcc-structures-design","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>With usual notations the depth of the neutral axis of a balanced section, is given by A. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} - {\\text{n}}}}{{\\text{n}}}$$ B. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{\\text{n}}}{{{\\text{d}} - {\\text{n}}}}$$ C. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{{\\text{d}} + {\\text{n}}}}{{\\text{n}}}$$ D. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{\\text{n}}}{{{\\text{d}} - {\\text{n}}}}$$<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"With usual notations the depth of the neutral axis of a balanced section, is given by A. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} - {\\text{n}}}}{{\\text{n}}}$$ B. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{\\text{n}}}{{{\\text{d}} - {\\text{n}}}}$$ C. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{{\\text{d}} + {\\text{n}}}}{{\\text{n}}}$$ D. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{\\text{n}}}{{{\\text{d}} - {\\text{n}}}}$$\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;$$frac{{{text{mc}}}}{{text{t}}} = frac{{{text{d}} &#8211; 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{text{n}}}}{{text{n}}}$$&#8221; option2=&#8221;$$frac{{text{t}}}{{{text{mc}}}} = frac{{text{n}}}{{{text{d}} &#8211; {text{n}}}}$$&#8221; option3=&#8221;$$frac{{text{t}}}{{{text{mc}}}} = frac{{{text{d}} + {text{n}}}}{{text{n}}}$$&#8221; option4=&#8221;$$frac{{{text{mc}}}}{{text{t}}} = frac{{text{n}}}{{{text{d}} &#8211; {text{n}}}}$$&#8221; correct=&#8221;option1&#8243;]","og_url":"https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2024-04-15T02:20:10+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"2 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/","url":"https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/","name":"With usual notations the depth of the neutral axis of a balanced section, is given by A. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} - {\\text{n}}}}{{\\text{n}}}$$ B. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{\\text{n}}}{{{\\text{d}} - {\\text{n}}}}$$ C. $$\\frac{{\\text{t}}}{{{\\text{mc}}}} = \\frac{{{\\text{d}} + {\\text{n}}}}{{\\text{n}}}$$ D. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{\\text{n}}}{{{\\text{d}} - {\\text{n}}}}$$","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2024-04-15T02:20:10+00:00","dateModified":"2024-04-15T02:20:10+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/with-usual-notations-the-depth-of-the-neutral-axis-of-a-balanced-section-is-given-by-a-fractextmctextt-fractextd-textntextn-b-fractext\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"mcq","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/"},{"@type":"ListItem","position":3,"name":"Civil engineering","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/civil-engineering\/"},{"@type":"ListItem","position":4,"name":"Rcc structures design","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/civil-engineering\/rcc-structures-design\/"},{"@type":"ListItem","position":5,"name":"With usual notations the depth of the neutral axis of a balanced section, is given by A. $$\\frac{{{\\text{mc}}}}{{\\text{t}}} = \\frac{{{\\text{d}} &#8211; 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