[amp_mcq option1=”$$\\frac{1}{3}{\\text{A}}$$” option2=”$$\\frac{1}{6}{\\text{A}}$$” option3=”$$\\frac{1}{{12}}{\\text{A}}$$” option4=”$$\\frac{1}{{18}}{\\text{A}}$$” correct=”option1″]<\/p>\n
The correct answer is $\\boxed{\\frac{1}{3}{\\text{A}}}$.<\/p>\n
The area of the core of a column is the area of the column minus the area of the outer shell. The area of the outer shell is a circle with radius $r$, so its area is $\\pi r^2$. The area of the column is a rectangle with width $2r$ and height $h$, so its area is $2rh$. Therefore, the area of the core is $2rh – \\pi r^2 = \\frac{2r^2}{3} – \\pi r^2 = \\frac{1}{3}{\\text{A}}$.<\/p>\n
Option A is incorrect because it is the area of a circle with radius $r$. Option B is incorrect because it is the area of a semicircle with radius $r$. Option C is incorrect because it is the area of a quarter circle with radius $r$. Option D is incorrect because it is the area of a sixth of a circle with radius $r$.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”$$\\frac{1}{3}{\\text{A}}$$” option2=”$$\\frac{1}{6}{\\text{A}}$$” option3=”$$\\frac{1}{{12}}{\\text{A}}$$” option4=”$$\\frac{1}{{18}}{\\text{A}}$$” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[639],"tags":[],"class_list":["post-5692","post","type-post","status-publish","format-standard","hentry","category-theory-of-structures","no-featured-image-padding"],"yoast_head":"\n