[amp_mcq option1=”$$\\frac{{\\text{L}}}{2}$$” option2=”$$\\frac{{\\text{L}}}{3}$$” option3=”$$\\frac{{\\text{L}}}{4}$$” option4=”$$\\frac{{\\text{L}}}{5}$$” correct=”option1″]<\/p>\n
The correct answer is $\\boxed{\\frac{{\\text{L}}}{2}}$.<\/p>\n
A plastic hinge is a region in a beam where the material has yielded and is undergoing plastic deformation. The length of the plastic hinge is determined by the following equation:<\/p>\n
$$L_p = \\frac{M_p}{\\sigma_y}$$<\/p>\n
where $M_p$ is the plastic moment of the beam, $\\sigma_y$ is the yield stress of the material, and $L_p$ is the length of the plastic hinge.<\/p>\n
For a simply supported I-section beam of span $L$ and loaded with a central load $W$, the plastic moment is given by the following equation:<\/p>\n
$$M_p = \\frac{WL^2}{8}$$<\/p>\n
The yield stress of steel is typically 250 MPa. Therefore, the length of the plastic hinge is given by the following equation:<\/p>\n
$$L_p = \\frac{\\frac{WL^2}{8}}{{250 \\text{ MPa}}} = \\frac{{\\text{L}}}{2}$$<\/p>\n
The other options are incorrect because they do not represent the correct length of the plastic hinge.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”$$\\frac{{\\text{L}}}{2}$$” option2=”$$\\frac{{\\text{L}}}{3}$$” option3=”$$\\frac{{\\text{L}}}{4}$$” option4=”$$\\frac{{\\text{L}}}{5}$$” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[639],"tags":[],"class_list":["post-5688","post","type-post","status-publish","format-standard","hentry","category-theory-of-structures","no-featured-image-padding"],"yoast_head":"\n