{"id":5662,"date":"2024-04-15T02:16:56","date_gmt":"2024-04-15T02:16:56","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=5662"},"modified":"2024-04-15T02:16:56","modified_gmt":"2024-04-15T02:16:56","slug":"a-simply-supported-beam-which-carries-a-uniformly-distributed-load-has-two-equal-overhangs-to-have-maximum-b-m-produced-in-the-beam-least-possible-the-ratio-of-the-length-of-the-overhang-to-the-tot","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-simply-supported-beam-which-carries-a-uniformly-distributed-load-has-two-equal-overhangs-to-have-maximum-b-m-produced-in-the-beam-least-possible-the-ratio-of-the-length-of-the-overhang-to-the-tot\/","title":{"rendered":"A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is A. 0.207 B. 0.307 C. 0.407 D. 0.508"},"content":{"rendered":"

[amp_mcq option1=”0.207″ option2=”0.307″ option3=”0.407″ option4=”0.508″ correct=”option1″]<\/p>\n

The correct answer is $\\boxed{\\text{A. }0.207}$.<\/p>\n

The maximum bending moment in a simply supported beam with two equal overhangs occurs at the support, and is equal to $wL^2\/8$, where $w$ is the uniform load per unit length and $L$ is the total length of the beam. The ratio of the length of the overhang to the total length of the beam is $a\/L$.<\/p>\n

To minimize the maximum bending moment, we need to minimize $a\/L$. The minimum value of $a\/L$ is 0.207, which occurs when $a=0.207L$.<\/p>\n

Here is a diagram of a simply supported beam with two equal overhangs:<\/p>\n

[Diagram of a simply supported beam with two equal overhangs]<\/p>\n

The maximum bending moment occurs at the support, and is equal to $wL^2\/8$. The ratio of the length of the overhang to the total length of the beam is $a\/L$.<\/p>\n

The following are brief explanations of each option:<\/p>\n