[amp_mcq option1=”Farad” option2=”Henry” option3=”Ohm” option4=”None of the above” correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\text{None of the above}}$.<\/p>\n
The dimensions of L\/CR are that of time. This can be seen by considering the following equation:<\/p>\n
$$L\\frac{di}{dt} = -CRV$$<\/p>\n
where $L$ is the inductance, $C$ is the capacitance, $R$ is the resistance, $i$ is the current, and $V$ is the voltage.<\/p>\n
If we divide both sides of this equation by $C$, we get:<\/p>\n
$$\\frac{L}{C}\\frac{di}{dt} = -RV$$<\/p>\n
The left-hand side of this equation has the dimensions of time, since it is the ratio of two quantities with dimensions of inductance and capacitance. The right-hand side of this equation has the dimensions of voltage, since it is the product of a quantity with dimensions of resistance and a quantity with dimensions of current. Therefore, the dimensions of L\/CR must be time.<\/p>\n
Option A, Farad, is the unit of capacitance. Option B, Henry, is the unit of inductance. Option C, Ohm, is the unit of resistance. None of these units are time.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”Farad” option2=”Henry” option3=”Ohm” option4=”None of the above” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[970],"tags":[],"class_list":["post-56393","post","type-post","status-publish","format-standard","hentry","category-transistors","no-featured-image-padding"],"yoast_head":"\n