{"id":55677,"date":"2024-04-16T00:31:27","date_gmt":"2024-04-16T00:31:27","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=55677"},"modified":"2024-04-16T00:31:27","modified_gmt":"2024-04-16T00:31:27","slug":"the-accuracy-of-the-floating-point-numbers-representable-in-two-16-bit-words-of-a-computer-is-approximately","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-accuracy-of-the-floating-point-numbers-representable-in-two-16-bit-words-of-a-computer-is-approximately\/","title":{"rendered":"The accuracy of the floating point numbers representable in two 16 bit words of a computer is approximately"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;16 digits&#8221; option2=&#8221;6 digits&#8221; option3=&#8221;4 digits&#8221; option4=&#8221;All of the above E. None of the above&#8221; correct=&#8221;option2&#8243;]<!--more--><\/p>\n<p>The correct answer is <strong>B. 6 digits<\/strong>.<\/p>\n<p>A 16-bit word can store 2^16 = 65536 different values. A floating point number is stored in a 16-bit word as a sign bit, an exponent, and a significand. The sign bit indicates whether the number is positive or negative. The exponent is a 4-bit number that indicates the power of 2 to which the significand should be raised. The significand is a 12-bit number that represents the fractional part of the number.<\/p>\n<p>The accuracy of a floating point number is determined by the number of digits that can be stored in the significand. A 12-bit significand can store 12 digits of precision. Therefore, the accuracy of a floating point number representable in two 16 bit words of a computer is approximately 6 digits.<\/p>\n<p>Option A is incorrect because it states that the accuracy is 16 digits. This is not possible because a 16-bit word can only store 16 bits of information.<\/p>\n<p>Option C is incorrect because it states that the accuracy is 4 digits. This is not possible because a 12-bit significand can store 12 digits of precision.<\/p>\n<p>Option D is incorrect because it states that all of the above are correct. This is not possible because option A is incorrect and option C is incorrect.<\/p>\n<p>Option E is correct because it states that none of the above are correct.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;16 digits&#8221; option2=&#8221;6 digits&#8221; option3=&#8221;4 digits&#8221; option4=&#8221;All of the above E. None of the above&#8221; correct=&#8221;option2&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[727],"tags":[],"class_list":["post-55677","post","type-post","status-publish","format-standard","hentry","category-computer-fundamental-miscellaneous","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>The accuracy of the floating point numbers representable in two 16 bit words of a computer is approximately<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/the-accuracy-of-the-floating-point-numbers-representable-in-two-16-bit-words-of-a-computer-is-approximately\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"The accuracy of the floating point numbers representable in two 16 bit words of a computer is approximately\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;16 digits&#8221; option2=&#8221;6 digits&#8221; option3=&#8221;4 digits&#8221; option4=&#8221;All of the above E. 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