{"id":54967,"date":"2024-04-16T00:19:19","date_gmt":"2024-04-16T00:19:19","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=54967"},"modified":"2024-04-16T00:19:19","modified_gmt":"2024-04-16T00:19:19","slug":"for-the-same-peak-value-which-of-the-following-wave-will-have-the-highest-r-m-s-value","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/for-the-same-peak-value-which-of-the-following-wave-will-have-the-highest-r-m-s-value\/","title":{"rendered":"For the same peak value which of the following wave will &#8216;have the highest r.m.s. value?"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;Square wave&#8221; option2=&#8221;Half wave rectified sine wave&#8221; option3=&#8221;Triangular wave&#8221; option4=&#8221;Sine wave&#8221; correct=&#8221;option1&#8243;]<!--more--><\/p>\n<p>The correct answer is: A. Square wave<\/p>\n<p>The root mean square (RMS) value of a waveform is the square root of the average of the squares of the instantaneous values of the waveform. In other words, it is the effective value of the waveform, which is the value that would produce the same heating effect in a resistor as a direct current of the same value.<\/p>\n<p>The RMS value of a sine wave is equal to its peak value divided by $\\sqrt{2}$. This is because the sine wave is symmetrical about its mean value, so the positive and negative half-cycles are equal in area. The RMS value of a square wave is equal to its peak value. This is because the square wave is not symmetrical about its mean value, so the positive half-cycle has a larger area than the negative half-cycle. The RMS value of a half-wave rectified sine wave is equal to its peak value divided by $\\sqrt{2}$. This is because the half-wave rectified sine wave is symmetrical about its mean value, but it only has one half-cycle. The RMS value of a triangular wave is equal to its peak value divided by $\\sqrt{3}$. This is because the triangular wave is not symmetrical about its mean value, and its positive half-cycle has a larger area than its negative half-cycle.<\/p>\n<p>Therefore, the square wave has the highest RMS value for the same peak value.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;Square wave&#8221; option2=&#8221;Half wave rectified sine wave&#8221; option3=&#8221;Triangular wave&#8221; option4=&#8221;Sine wave&#8221; correct=&#8221;option1&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[739],"tags":[],"class_list":["post-54967","post","type-post","status-publish","format-standard","hentry","category-a-c-fundamentals-circuits-and-circuit-theory","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>For the same peak value which of the following wave will &#039;have the highest r.m.s. value?<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/for-the-same-peak-value-which-of-the-following-wave-will-have-the-highest-r-m-s-value\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"For the same peak value which of the following wave will &#039;have the highest r.m.s. value?\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;Square wave&#8221; 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