{"id":54735,"date":"2024-04-16T00:15:15","date_gmt":"2024-04-16T00:15:15","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=54735"},"modified":"2024-04-16T00:15:15","modified_gmt":"2024-04-16T00:15:15","slug":"if-the-current-gain-of-the-amplifier-is-x-its-voltage-gain-is-y-then-its-power-gain-will-be","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-the-current-gain-of-the-amplifier-is-x-its-voltage-gain-is-y-then-its-power-gain-will-be\/","title":{"rendered":"If the current gain of the amplifier is X, its voltage gain is Y, then its power gain will be"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;$$\\frac{{\\text{X}}}{{\\text{Y}}}$$&#8221; option2=&#8221;X \u00c3\u0097 Y&#8221; option3=&#8221;X + Y&#8221; option4=&#8221;X &#8211; Y&#8221; correct=&#8221;option2&#8243;]<!--more--><\/p>\n<p>The correct answer is B. X \u00c3\u0097 Y.<\/p>\n<p>The power gain of an amplifier is the ratio of the output power to the input power. It is a measure of how much the amplifier amplifies the power of the input signal.<\/p>\n<p>The current gain of an amplifier is the ratio of the output current to the input current. The voltage gain of an amplifier is the ratio of the output voltage to the input voltage.<\/p>\n<p>The power gain of an amplifier can be calculated using the following equation:<\/p>\n<p>Power gain = Current gain \u00c3\u0097 Voltage gain<\/p>\n<p>Therefore, if the current gain of the amplifier is X and its voltage gain is Y, then its power gain will be X \u00c3\u0097 Y.<\/p>\n<p>Option A is incorrect because it is the reciprocal of the power gain. Option C is incorrect because it is the sum of the current gain and the voltage gain. Option D is incorrect because it is the difference between the current gain and the voltage gain.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;$$\\frac{{\\text{X}}}{{\\text{Y}}}$$&#8221; option2=&#8221;X \u00c3\u0097 Y&#8221; option3=&#8221;X + Y&#8221; option4=&#8221;X &#8211; Y&#8221; correct=&#8221;option2&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[740],"tags":[],"class_list":["post-54735","post","type-post","status-publish","format-standard","hentry","category-electronics-and-instrumentation","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If the current gain of the amplifier is X, its voltage gain is Y, then its power gain will be<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-current-gain-of-the-amplifier-is-x-its-voltage-gain-is-y-then-its-power-gain-will-be\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If the current gain of the amplifier is X, its voltage gain is Y, then its power gain will be\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;$$frac{{text{X}}}{{text{Y}}}$$&#8221; 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