[amp_mcq option1=”0.024 F” option2=”0.12 F” option3=”0.6 F” option4=”0.8 F” correct=”option3″]<\/p>\n
The correct answer is C. 0.6 F.<\/p>\n
The capacitance of a capacitor is defined as the ratio of the charge stored on it to the voltage across it. In this case, the capacitor stores 0.24 coulombs of charge at a voltage of 10 volts. Therefore, its capacitance is $C = \\frac{Q}{V} = \\frac{0.24 \\text{ C}}{10 \\text{ V}} = 0.24 \\text{ F}$.<\/p>\n
Option A is incorrect because it is the capacitance of a capacitor that stores 0.024 coulombs of charge at a voltage of 10 volts. Option B is incorrect because it is the capacitance of a capacitor that stores 0.12 coulombs of charge at a voltage of 10 volts. Option D is incorrect because it is the capacitance of a capacitor that stores 0.8 coulombs of charge at a voltage of 10 volts.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”0.024 F” option2=”0.12 F” option3=”0.6 F” option4=”0.8 F” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[971],"tags":[],"class_list":["post-51760","post","type-post","status-publish","format-standard","hentry","category-electrostatics","no-featured-image-padding"],"yoast_head":"\n