{"id":51432,"date":"2024-04-15T23:24:44","date_gmt":"2024-04-15T23:24:44","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=51432"},"modified":"2024-04-15T23:24:44","modified_gmt":"2024-04-15T23:24:44","slug":"in-an-ac-co-ordinate-potentiometer-the-currents-in-the-phase-and-quadrature-potentiometer-are-adjusted-to-be","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/in-an-ac-co-ordinate-potentiometer-the-currents-in-the-phase-and-quadrature-potentiometer-are-adjusted-to-be\/","title":{"rendered":"In an AC co-ordinate potentiometer, the currents in the phase and quadrature potentiometer are adjusted to be"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;out of phase by 90\u00c2\u00b0&#8221; option2=&#8221;out of phase by 60\u00c2\u00b0&#8221; option3=&#8221;out of phase by 30\u00c2\u00b0&#8221; option4=&#8221;out of phase by 0\u00c2\u00b0&#8221; correct=&#8221;option1&#8243;]<!--more--><\/p>\n<p>The correct answer is A. out of phase by 90\u00c2\u00b0.<\/p>\n<p>In an AC co-ordinate potentiometer, the currents in the phase and quadrature potentiometers are adjusted to be out of phase by 90\u00c2\u00b0. This is done to ensure that the output of the potentiometer is a pure sine wave. If the currents were not out of phase by 90\u00c2\u00b0, the output would be a distorted sine wave.<\/p>\n<p>The phase potentiometer is used to control the phase angle of the output signal. The quadrature potentiometer is used to control the amplitude of the output signal. By adjusting the settings of the two potentiometers, the output signal can be controlled to be a pure sine wave.<\/p>\n<p>The following is a brief explanation of each option:<\/p>\n<ul>\n<li>Option A: out of phase by 90\u00c2\u00b0. This is the correct answer. The currents in the phase and quadrature potentiometers are adjusted to be out of phase by 90\u00c2\u00b0 to ensure that the output of the potentiometer is a pure sine wave.<\/li>\n<li>Option B: out of phase by 60\u00c2\u00b0. This is not the correct answer. The currents in the phase and quadrature potentiometers are not adjusted to be out of phase by 60\u00c2\u00b0.<\/li>\n<li>Option C: out of phase by 30\u00c2\u00b0. This is not the correct answer. The currents in the phase and quadrature potentiometers are not adjusted to be out of phase by 30\u00c2\u00b0.<\/li>\n<li>Option D: out of phase by 0\u00c2\u00b0. This is not the correct answer. The currents in the phase and quadrature potentiometers are not adjusted to be out of phase by 0\u00c2\u00b0.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;out of phase by 90\u00c2\u00b0&#8221; option2=&#8221;out of phase by 60\u00c2\u00b0&#8221; option3=&#8221;out of phase by 30\u00c2\u00b0&#8221; option4=&#8221;out of phase by 0\u00c2\u00b0&#8221; correct=&#8221;option1&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[741],"tags":[],"class_list":["post-51432","post","type-post","status-publish","format-standard","hentry","category-electrical-machine-design","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>In an AC co-ordinate potentiometer, the currents in the phase and quadrature potentiometer are adjusted to be<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/in-an-ac-co-ordinate-potentiometer-the-currents-in-the-phase-and-quadrature-potentiometer-are-adjusted-to-be\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"In an AC co-ordinate potentiometer, the currents in the phase and quadrature potentiometer are adjusted to be\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;out of phase by 90\u00c2\u00b0&#8221; 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