[amp_mcq option1=”50 joules” option2=”150 joules” option3=”200 joules” option4=”250 joules” correct=”option3″]<\/p>\n
The correct answer is $\\boxed{\\text{C. 200 joules}}$.<\/p>\n
The energy stored in a capacitor is given by the equation:<\/p>\n
$$E = \\frac{1}{2}CV^2$$<\/p>\n
where $C$ is the capacitance in farads, $V$ is the potential difference in volts, and $E$ is the energy stored in joules.<\/p>\n
In this case, we are given that $C = 5 \\mu F$ and $V = 10,000 V$. Substituting these values into the equation, we get:<\/p>\n
$$E = \\frac{1}{2}(5 \\mu F)(10,000 V)^2 = 200 \\text{ joules}$$<\/p>\n
Therefore, the energy stored in the capacitor is 200 joules.<\/p>\n
Option A is incorrect because it is half the correct value. Option B is incorrect because it is twice the correct value. Option D is incorrect because it is four times the correct value.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”50 joules” option2=”150 joules” option3=”200 joules” option4=”250 joules” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[971],"tags":[],"class_list":["post-50379","post","type-post","status-publish","format-standard","hentry","category-electrostatics","no-featured-image-padding"],"yoast_head":"\n