{"id":48429,"date":"2024-04-15T22:41:07","date_gmt":"2024-04-15T22:41:07","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=48429"},"modified":"2024-04-15T22:41:07","modified_gmt":"2024-04-15T22:41:07","slug":"what-will-be-energy-used-by-the-battery-if-the-battery-has-to-drive-6-28-x-1018-electrons-with-potential-difference-of-20-v-across-the-terminal","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/what-will-be-energy-used-by-the-battery-if-the-battery-has-to-drive-6-28-x-1018-electrons-with-potential-difference-of-20-v-across-the-terminal\/","title":{"rendered":"What will be energy used by the battery if the battery has to drive 6.28 x 1018 electrons with potential difference of 20 V across the terminal?"},"content":{"rendered":"<p>[amp_mcq option1=&#8221;5 joules&#8221; option2=&#8221;10 joules&#8221; option3=&#8221;15 joules&#8221; option4=&#8221;20 joules&#8221; correct=&#8221;option3&#8243;]<!--more--><\/p>\n<p>The correct answer is $\\boxed{\\text{D}}$.<\/p>\n<p>The energy used by the battery is given by the equation $E = QV$, where $Q$ is the charge and $V$ is the potential difference. In this case, $Q = 6.28 \\times 10^{18}$ electrons and $V = 20$ V, so the energy used is $E = 6.28 \\times 10^{18} \\times 20 = 12.56 \\times 10^{19}$ J. This is equivalent to 12.56 kilojoules, or 12.56 thousand joules.<\/p>\n<p>Option A is incorrect because it is too small. The energy used by the battery is proportional to the charge, and the charge in this case is $6.28 \\times 10^{18}$ electrons, which is much larger than the charge in option A.<\/p>\n<p>Option B is incorrect because it is too small. The energy used by the battery is proportional to the potential difference, and the potential difference in this case is 20 V, which is much larger than the potential difference in option B.<\/p>\n<p>Option C is incorrect because it is too small. The energy used by the battery is proportional to the product of the charge and the potential difference, and the product of the charge and the potential difference in this case is $6.28 \\times 10^{18} \\times 20 = 12.56 \\times 10^{19}$ J, which is much larger than the energy used in option C.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>[amp_mcq option1=&#8221;5 joules&#8221; option2=&#8221;10 joules&#8221; option3=&#8221;15 joules&#8221; option4=&#8221;20 joules&#8221; correct=&#8221;option3&#8243;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[948],"tags":[],"class_list":["post-48429","post","type-post","status-publish","format-standard","hentry","category-current-electricity","no-featured-image-padding"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>What will be energy used by the battery if the battery has to drive 6.28 x 1018 electrons with potential difference of 20 V across the terminal?<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/what-will-be-energy-used-by-the-battery-if-the-battery-has-to-drive-6-28-x-1018-electrons-with-potential-difference-of-20-v-across-the-terminal\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"What will be energy used by the battery if the battery has to drive 6.28 x 1018 electrons with potential difference of 20 V across the terminal?\" \/>\n<meta property=\"og:description\" content=\"[amp_mcq option1=&#8221;5 joules&#8221; 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