[amp_mcq option1=”Falls to 36.8% of its final steady value” option2=”Rises to 38.6% of its final steady value” option3=”Rises to 63.2% of its final steady value” option4=”None of the above” correct=”option3″]<\/p>\n
The correct answer is: C. Rises to 63.2% of its final steady value.<\/p>\n
The time constant of a capacitance circuit is the time it takes for the voltage across the capacitor to reach 63.2% of its final steady-state value. This is because the capacitor charges exponentially, and the time constant is the time it takes for the exponential function to reach 63.2% of its final value.<\/p>\n
Option A is incorrect because the voltage across the capacitor never falls to 36.8% of its final steady value. The voltage across the capacitor starts at 0% and then increases exponentially to its final steady-state value.<\/p>\n
Option B is incorrect because the voltage across the capacitor never rises to 38.6% of its final steady value. The voltage across the capacitor starts at 0% and then increases exponentially to its final steady-state value.<\/p>\n
Option D is incorrect because the time constant is defined as the time it takes for the voltage across the capacitor to reach 63.2% of its final steady-state value.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”Falls to 36.8% of its final steady value” option2=”Rises to 38.6% of its final steady value” option3=”Rises to 63.2% of its final steady value” option4=”None of the above” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[739],"tags":[],"class_list":["post-47429","post","type-post","status-publish","format-standard","hentry","category-a-c-fundamentals-circuits-and-circuit-theory","no-featured-image-padding"],"yoast_head":"\n