[amp_mcq option1=”14″ option2=”15″ option3=”18″ option4=”20″ correct=”option3″]<\/p>\n
The correct answer is (c) 18.<\/p>\n
The variance of a set of numbers is a measure of how spread out the numbers are. It is calculated by taking the square of the difference between each number and the mean, and then averaging those squares.<\/p>\n
In this case, the mean is $\\frac{(-3) + (-2) + 3 + 8 + 9 + 5 + 4 + 22 + 4 + 5}{10} = \\frac{43}{10}$.<\/p>\n
The squared deviations from the mean are:<\/p>\n
$(-3 – \\frac{43}{10})^2 = \\frac{9}{100}$
\n$(-2 – \\frac{43}{10})^2 = \\frac{49}{100}$
\n$(3 – \\frac{43}{10})^2 = \\frac{9}{100}$
\n$(8 – \\frac{43}{10})^2 = \\frac{169}{100}$
\n$(9 – \\frac{43}{10})^2 = \\frac{144}{100}$
\n$(5 – \\frac{43}{10})^2 = \\frac{49}{100}$
\n$(4 – \\frac{43}{10})^2 = \\frac{9}{100}$
\n$(22 – \\frac{43}{10})^2 = \\frac{329}{100}$
\n$(4 – \\frac{43}{10})^2 = \\frac{9}{100}$
\n$(5 – \\frac{43}{10})^2 = \\frac{49}{100}$<\/p>\n
The variance is then $\\frac{9}{100} + \\frac{49}{100} + \\frac{9}{100} + \\frac{169}{100} + \\frac{144}{100} + \\frac{49}{100} + \\frac{9}{100} + \\frac{329}{100} + \\frac{9}{100} + \\frac{49}{100} = \\frac{18}{5}$.<\/p>\n
Multiplying by 5 to get the variance in the original units, we get 18.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”14″ option2=”15″ option3=”18″ option4=”20″ correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[28],"tags":[],"class_list":["post-4689","post","type-post","status-publish","format-standard","hentry","category-statistics","no-featured-image-padding"],"yoast_head":"\n