{"id":45070,"date":"2024-04-15T21:52:49","date_gmt":"2024-04-15T21:52:49","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=45070"},"modified":"2024-04-15T21:52:49","modified_gmt":"2024-04-15T21:52:49","slug":"a-shunt-generator-running-at-1000-r-p-m-has-generated-e-m-f-as-200-v-if-the-speed-increases-to-1200-r-p-m-the-generated-e-m-f-will-be-nearly","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-shunt-generator-running-at-1000-r-p-m-has-generated-e-m-f-as-200-v-if-the-speed-increases-to-1200-r-p-m-the-generated-e-m-f-will-be-nearly\/","title":{"rendered":"A shunt generator running at 1000 r.p.m. has generated e.m.f. as 200 V. If the speed increases to 1200 r.p.m., the generated e.m.f. will be nearly"},"content":{"rendered":"

[amp_mcq option1=”150 V” option2=”175 V” option3=”240 V” option4=”290 V” correct=”option3″]<\/p>\n

The correct answer is C. 240 V.<\/p>\n

The e.m.f. of a shunt generator is proportional to the speed of the generator. Therefore, if the speed increases from 1000 r.p.m. to 1200 r.p.m., the e.m.f. will increase by a factor of 1200\/1000 = 1.2. The e.m.f. will therefore be 200 V x 1.2 = 240 V.<\/p>\n

Option A is incorrect because it is too low. Option B is incorrect because it is too close to the original e.m.f. Option D is incorrect because it is too high.<\/p>\n","protected":false},"excerpt":{"rendered":"

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If the speed increases to 1200 r.p.m., the generated e.m.f. will be nearly<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-shunt-generator-running-at-1000-r-p-m-has-generated-e-m-f-as-200-v-if-the-speed-increases-to-1200-r-p-m-the-generated-e-m-f-will-be-nearly\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A shunt generator running at 1000 r.p.m. has generated e.m.f. as 200 V. 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