{"id":4428,"date":"2024-03-05T16:06:09","date_gmt":"2024-03-05T16:06:09","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=4428"},"modified":"2024-03-05T16:06:09","modified_gmt":"2024-03-05T16:06:09","slug":"if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/","title":{"rendered":"If the sum of two numbers is 100 and their difference is 50, the ratio of the two numbers will be"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a978b448b646\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    02:01                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    03:01                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"true\">\r\n                    04:01                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    05:01                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is (c).<\/p>\n<p>Let $x$ and $y$ be the two numbers. We know that $x+y=100$ and $x-y=50$. Adding these two equations, we get $2x=150$, so $x=75$. <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> Substituting this into $x+y=100$, we get $75+y=100$, so $y=25$. Therefore, <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> the ratio of the two numbers is $\\frac{x}{y}=\\frac{75}{25}=\\boxed{3:1}$.<\/p>\n<p>Option (a) is incorrect because the sum of the two numbers is 100, not 50. Option (b) is incorrect because the difference of the two numbers is 50, not 25. Option (d) is incorrect because the ratio of the two numbers is 3:1, not 5:1.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[33],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If the sum of two numbers is 100 and their difference is 50, the ratio of the two numbers will be<\/title>\n<meta name=\"description\" content=\"Let $x$ and $y$ be the two numbers. We know that $x+y=100$ and $x-y=50$. Adding these two equations, we get $2x=150$, so $x=75$. Substituting this into $x+y=100$, we get $75+y=100$, so $y=25$. Therefore, the ratio of the two numbers is $frac{x}{y}=frac{75}{25}=boxed{3:1}$.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If the sum of two numbers is 100 and their difference is 50, the ratio of the two numbers will be\" \/>\n<meta property=\"og:description\" content=\"Let $x$ and $y$ be the two numbers. We know that $x+y=100$ and $x-y=50$. Adding these two equations, we get $2x=150$, so $x=75$. Substituting this into $x+y=100$, we get $75+y=100$, so $y=25$. Therefore, the ratio of the two numbers is $frac{x}{y}=frac{75}{25}=boxed{3:1}$.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2024-03-05T16:06:09+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If the sum of two numbers is 100 and their difference is 50, the ratio of the two numbers will be","description":"Let $x$ and $y$ be the two numbers. We know that $x+y=100$ and $x-y=50$. Adding these two equations, we get $2x=150$, so $x=75$. Substituting this into $x+y=100$, we get $75+y=100$, so $y=25$. Therefore, the ratio of the two numbers is $frac{x}{y}=frac{75}{25}=boxed{3:1}$.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/","og_locale":"en_US","og_type":"article","og_title":"If the sum of two numbers is 100 and their difference is 50, the ratio of the two numbers will be","og_description":"Let $x$ and $y$ be the two numbers. We know that $x+y=100$ and $x-y=50$. Adding these two equations, we get $2x=150$, so $x=75$. Substituting this into $x+y=100$, we get $75+y=100$, so $y=25$. Therefore, the ratio of the two numbers is $frac{x}{y}=frac{75}{25}=boxed{3:1}$.","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2024-03-05T16:06:09+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/","name":"If the sum of two numbers is 100 and their difference is 50, the ratio of the two numbers will be","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2024-03-05T16:06:09+00:00","dateModified":"2024-03-05T16:06:09+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"description":"Let $x$ and $y$ be the two numbers. We know that $x+y=100$ and $x-y=50$. Adding these two equations, we get $2x=150$, so $x=75$. Substituting this into $x+y=100$, we get $75+y=100$, so $y=25$. Therefore, the ratio of the two numbers is $\\frac{x}{y}=\\frac{75}{25}=\\boxed{3:1}$.","breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-sum-of-two-numbers-is-100-and-their-difference-is-50-the-ratio-of-the-two-numbers-will-be\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"mcq","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/"},{"@type":"ListItem","position":3,"name":"Algebra","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/algebra\/"},{"@type":"ListItem","position":4,"name":"If the sum of two numbers is 100 and their difference is 50, the ratio of the two numbers will be"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/4428"}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=4428"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/4428\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=4428"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=4428"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=4428"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}