[amp_mcq option1=”tg = 10-6, tp = 1.56″ option2=”tg = 1.56, tp = 10-6″ option3=”tg = 10-8, tp = 1.56 \u00c3\u0097 10-6″ option4=”tg = 108, tp = 1.56″ correct=”option4″]<\/p>\n
The correct answer is: $\\boxed{\\text{A. }tg = 10^{-6}, tp = 1.56}$.<\/p>\n
The group delay of a channel is the derivative of the phase delay with respect to frequency. In other words, it is the rate at which the phase of a signal changes with frequency. The phase delay of a channel is the angle by which a signal is delayed by the channel.<\/p>\n
The group delay and phase delay of a channel can be calculated from the transfer function of the channel. The transfer function of a channel is the ratio of the output signal to the input signal.<\/p>\n
The transfer function of the channel in this question is given by:<\/p>\n
$$H(j\\omega) = \\frac{1}{100 + j\\omega}$$<\/p>\n
The group delay of the channel is given by:<\/p>\n
$$\\tau_g = -\\frac{d}{d\\omega} \\arg{H(j\\omega)} = \\frac{1}{100}$$<\/p>\n
The phase delay of the channel is given by:<\/p>\n
$$\\tau_p = -\\arg{H(j\\omega)} = 1.56$$<\/p>\n
Therefore, the group delay and phase delay of the channel are $\\boxed{\\text{A. }tg = 10^{-6}, tp = 1.56}$.<\/p>\n
Here is a brief explanation of each option:<\/p>\n
[amp_mcq option1=”tg = 10-6, tp = 1.56″ option2=”tg = 1.56, tp = 10-6″ option3=”tg = 10-8, tp = 1.56 \u00c3\u0097 10-6″ option4=”tg = 108, tp = 1.56″ correct=”option4″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[959],"tags":[],"class_list":["post-43872","post","type-post","status-publish","format-standard","hentry","category-signal-processing","no-featured-image-padding"],"yoast_head":"\n