{"id":41693,"date":"2024-04-15T11:26:46","date_gmt":"2024-04-15T11:26:46","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=41693"},"modified":"2024-04-15T11:26:46","modified_gmt":"2024-04-15T11:26:46","slug":"1-4-1-8-1-3","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/1-4-1-8-1-3\/","title":{"rendered":"(1\/4) : (1\/8) :: (1\/3) : ?"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a99db2836143\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"true\">\r\n                    01-Jul                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    01-Apr                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    01-Jun                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    01-Feb                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The answer is $\\boxed{\\frac{1}{6}}$.<\/p>\n<p>To solve this question, we can use the rule of three. The rule of three states that if three quantities are in proportion, then the fourth quantity is also in proportion to the first three. In other words, if $a:b::c:d$, then $a:c=b:d$.<\/p>\n<p>In this question, we are given that $\\frac{1}{4}:\\frac{1}{8}::\\frac{1}{3}:x$. We can set up a proportion as follows:<\/p>\n<p>$$\\frac{1}{4}:\\frac{1}{8}=\\frac{1}{3}:x$$<\/p>\n<p>Cross-multiplying, we get:<\/p>\n<p>$$\\frac{1}{4}x=\\frac{1}{8}\\times\\frac{1}{3}$$<\/p>\n<p>$$x=\\frac{1}{8}\\times\\frac{1}{3}\\times\\frac{4}{1}$$<\/p>\n<p>$$x=\\frac{1}{6}$$<\/p>\n<p>Therefore, the answer is $\\boxed{\\frac{1}{6}}$.<\/p>\n<p>We can also solve this question by multiplying the two ratios together. The product of two ratios is the same as the ratio of the products of the corresponding terms. In other words, if $a:b::c:d$, <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n           <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div>          <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> then $a\\times c:b\\times d$.<\/p>\n<p>In this question, we are given that $\\frac{1}{4}:\\frac{1}{8}::\\frac{1}{3}:x$. We can multiply the two ratios together as follows:<\/p>\n<p>$$\\frac{1}{4}\\times\\frac{1}{3}:\\frac{1}{8}\\times x=\\frac{1}{12}:x$$<\/p>\n<p>$$x=\\frac{1}{12}\\times\\frac{8}{1}=\\frac{1}{6}$$<\/p>\n<p>Therefore, the answer is $\\boxed{\\frac{1}{6}}$.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[714],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>(1\/4) : (1\/8) :: (1\/3) : ?<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/1-4-1-8-1-3\/\" \/>\n<meta property=\"og:locale\" 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