{"id":3622,"date":"2024-03-05T15:53:12","date_gmt":"2024-03-05T15:53:12","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=3622"},"modified":"2024-03-05T15:53:12","modified_gmt":"2024-03-05T15:53:12","slug":"if-it-was-monday-on-january-15th-1989-what-day-it-would-had-been-on-january-20-1990-2","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-it-was-monday-on-january-15th-1989-what-day-it-would-had-been-on-january-20-1990-2\/","title":{"rendered":"If it was Monday on January 15th 1989, what day it would had been on January 20, 1990?"},"content":{"rendered":"

[amp_mcq option1=”Sunday” option2=”Monday” option3=”Tuesday” option4=”Wednesday ” correct=”option2″]<\/p>\n

The correct answer is (b).<\/p>\n

A common way to solve this problem is to use the following formula:<\/p>\n

Day on January 20, 1990 = (Day on January 15, 1989 + 365 days) mod 7<\/p>\n

In this case, January 15, 1989 is a Monday. Adding 365 days to this gives us February 28, 1990. This is a leap year, so we need to add 1 day to get March 1, 1990. March 1, 1990 is a Tuesday. Modulo 7, this gives us 2, which is Monday.<\/p>\n

Another way to solve this problem is to use a calendar. If you look at a calendar for 1989, you will see that January 15 is a Monday. If you then look at a calendar for 1990, you will see that January 20 is also a Monday.<\/p>\n

The other options are incorrect because they do not follow the formula or the calendar.<\/p>\n","protected":false},"excerpt":{"rendered":"

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