[amp_mcq option1=”8″ option2=”9″ option3=”10″ option4=”11″ correct=”option2″]<\/p>\n
The correct answer is (b), 9.<\/p>\n
To solve this, we can use the following formula:<\/p>\n
$P = 2l + 2w$<\/p>\n
where $P$ is the perimeter, $l$ is the length, and $w$ is the width.<\/p>\n
We know that $P = 36$, so we can plug that in to the formula:<\/p>\n
$36 = 2l + 2w$<\/p>\n
$18 = l + w$<\/p>\n
Now, we can try different values for $l$ and $w$ to see if we can find any combinations that add up to 18.<\/p>\n
We know that $l$ and $w$ must both be positive integers, so we can start with the smallest possible values, which are 1 and 18.<\/p>\n
$1 + 18 = 19$<\/p>\n
This doesn’t work, so we can try the next smallest values, which are 2 and 16.<\/p>\n
$2 + 16 = 18$<\/p>\n
This works! So, one possible rectangle is 2 cm by 16 cm.<\/p>\n
We can keep trying different values for $l$ and $w$ until we find all of the possible combinations.<\/p>\n
Here are all of the possible rectangles of 36 cm perimeter:<\/p>\n
There are a total of 9 possible rectangles.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”8″ option2=”9″ option3=”10″ option4=”11″ correct=”option2″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[104],"tags":[],"class_list":["post-3151","post","type-post","status-publish","format-standard","hentry","category-combinatorics","no-featured-image-padding"],"yoast_head":"\n