{"id":23812,"date":"2024-04-15T06:38:35","date_gmt":"2024-04-15T06:38:35","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=23812"},"modified":"2024-04-15T06:38:35","modified_gmt":"2024-04-15T06:38:35","slug":"if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/","title":{"rendered":"If the equilibrium constants for the systems H2 + I2 -> 2HI and 2HI -> H2 + I2 are K1 and K2 respectively, the relationship between K1 and K2 is : A. K1 = K2 B. K1 = 2K2 C. K1 = K2\/2 D. K1= 1\/K2"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a9c4e1c0a439\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"true\">\r\n                    K1 = K2                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    K1 = 2K2                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    K1 = K2\/2                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    K1= 1\/K2                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: $\\boxed{K_1 = K_2^{-1}}$.<\/p>\n<p>The equilibrium constant for <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> a reaction is a measure of the extent to which the reaction proceeds to completion. It is defined as the ratio of the concentrations of the products to the concentrations of the reactants, each raised to the power of its stoichiometric coefficient.<\/p>\n<p>For the reaction $H_2 + I_2 \\rightleftharpoons 2HI$, the equilibrium constant is $K_1$. For the reaction $2HI \\rightleftharpoons H_2 + I_2$, the equilibrium constant is $K_2$.<\/p>\n<p>The relationship between $K_1$ and $K_2$ can be determined by considering the following equation:<\/p>\n<p>$$K_1 = \\frac{[HI]^2}{[H_2][I_2]}$$<\/p>\n<p>$$K_2 = \\frac{[H_2][I_2]}{[HI]^2}$$<\/p>\n<p>Taking the reciprocal of both sides of the second equation, we get:<\/p>\n<p>$$\\frac{1}{K_2} = \\frac{[HI]^2}{[H_2][I_2]}$$<\/p>\n<p>Substituting this into the first equation, we get:<\/p>\n<p>$$K_1 = \\frac{1}{K_2}$$<\/p>\n<p>Therefore, the relationship between $K_1$ and $K_2$ is $K_1 = K_2^{-1}$.<\/p>\n<p>Here is a brief explanation of each option:<\/p>\n<ul>\n<li>Option A: $K_1 = K_2$. This is not the correct answer because the equilibrium constants for the two reactions are not equal.<\/li>\n<li>Option B: $K_1 = 2K_2$. This is not the correct answer because the equilibrium constants for the two reactions are not in a simple ratio.<\/li>\n<li>Option C: $K_1 = K_2\/2$. This is not the correct answer because the equilibrium constants for the two reactions are not in a simple ratio.<\/li>\n<li>Option D: $K_1 <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> = 1\/K_2$. This is the correct answer because the equilibrium constants for the two reactions are in an inverse relationship.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[19],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>If the equilibrium constants for the systems H2 + I2 -&gt; 2HI and 2HI -&gt; H2 + I2 are K1 and K2 respectively, the relationship between K1 and K2 is : A. K1 = K2 B. K1 = 2K2 C. K1 = K2\/2 D. K1= 1\/K2<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"If the equilibrium constants for the systems H2 + I2 -&gt; 2HI and 2HI -&gt; H2 + I2 are K1 and K2 respectively, the relationship between K1 and K2 is : A. K1 = K2 B. K1 = 2K2 C. K1 = K2\/2 D. K1= 1\/K2\" \/>\n<meta property=\"og:description\" content=\"Join Our Telegram Channel Subscribe on YouTube\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2024-04-15T06:38:35+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"If the equilibrium constants for the systems H2 + I2 -> 2HI and 2HI -> H2 + I2 are K1 and K2 respectively, the relationship between K1 and K2 is : A. K1 = K2 B. K1 = 2K2 C. K1 = K2\/2 D. K1= 1\/K2","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/","og_locale":"en_US","og_type":"article","og_title":"If the equilibrium constants for the systems H2 + I2 -> 2HI and 2HI -> H2 + I2 are K1 and K2 respectively, the relationship between K1 and K2 is : A. K1 = K2 B. K1 = 2K2 C. K1 = K2\/2 D. K1= 1\/K2","og_description":"Join Our Telegram Channel Subscribe on YouTube","og_url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2024-04-15T06:38:35+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/","url":"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/","name":"If the equilibrium constants for the systems H2 + I2 -> 2HI and 2HI -> H2 + I2 are K1 and K2 respectively, the relationship between K1 and K2 is : A. K1 = K2 B. K1 = 2K2 C. K1 = K2\/2 D. K1= 1\/K2","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2024-04-15T06:38:35+00:00","dateModified":"2024-04-15T06:38:35+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/if-the-equilibrium-constants-for-the-systems-h2-i2-2hi-and-2hi-h2-i2-are-k1-and-k2-respectively-the-relationship-between-k1-and-k2-is-a-k1-k2-b-k1-2k2-c-k1-k2-2-d-k1-1-k2\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"mcq","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/"},{"@type":"ListItem","position":3,"name":"chemistry","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/chemistry\/"},{"@type":"ListItem","position":4,"name":"If the equilibrium constants for the systems H2 + I2 -> 2HI and 2HI -> H2 + I2 are K1 and K2 respectively, the relationship between K1 and K2 is : A. K1 = K2 B. K1 = 2K2 C. K1 = K2\/2 D. K1= 1\/K2"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/23812"}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=23812"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/23812\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=23812"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=23812"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=23812"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}