{"id":23783,"date":"2024-04-15T06:38:11","date_gmt":"2024-04-15T06:38:11","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=23783"},"modified":"2024-04-15T06:38:11","modified_gmt":"2024-04-15T06:38:11","slug":"the-reaction-intermediate-formed-during-the-preparation-of-diethyl-ether-from-ethanol-by-treatment-with-h2so4-is-a-carbanion-b-carbocation-c-carbene-d-free-radical","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/the-reaction-intermediate-formed-during-the-preparation-of-diethyl-ether-from-ethanol-by-treatment-with-h2so4-is-a-carbanion-b-carbocation-c-carbene-d-free-radical\/","title":{"rendered":"The reaction intermediate formed during the preparation of diethyl ether from ethanol by treatment with H2SO4 is A. Carbanion B. Carbocation C. Carbene D. Free radical"},"content":{"rendered":"

[amp_mcq option1=”Carbanion” option2=”Carbocation” option3=”Carbene” option4=”Free radical” correct=”option3″]<\/p>\n

The correct answer is carbocation<\/strong>.<\/p>\n

A carbocation is a positively charged carbon atom. It is formed when a proton (H+) is removed from a molecule, leaving behind a carbon atom with an incomplete octet. Carbocations are very reactive and can undergo a variety of reactions, including substitution, addition, and elimination.<\/p>\n

In the preparation of diethyl ether from ethanol by treatment with H2SO4, the first step is the protonation of ethanol. This forms the ethyl carbocation, which is then attacked by the ethoxide ion (the conjugate base of ethanol) to form diethyl ether.<\/p>\n

The reaction mechanism is as follows:<\/p>\n

$$\\ce{EtOH + H2SO4 <=> EtOH^+ + HSO4^-}$$
\n$$\\ce{EtOH^+ + EtO^- <=> Et-O-Et + H2O}$$<\/p>\n

The ethyl carbocation is a very reactive intermediate and can undergo a variety of reactions. In this case, it reacts with the ethoxide ion to form diethyl ether.<\/p>\n

The other options are incorrect.<\/p>\n