[amp_mcq option1=”-4.33 diopters” option2=”12.33 diopters” option3=”-12.33 diopters” option4=”4.33 diopters” correct=”option1″]<\/p>\n
The correct answer is $\\boxed{\\text{A. }-4.33 \\text{ diopters}}$.<\/p>\n
The power of a lens is given by the formula:<\/p>\n
$$P = \\frac{1}{f}$$<\/p>\n
where $f$ is the focal length of the lens in meters.<\/p>\n
The focal length of a convex lens is positive, so the power of a convex lens is also positive.<\/p>\n
The image formed by a convex lens is real and inverted when the object is placed between the optical center and the focal point of the lens.<\/p>\n
In this case, the object is placed at a distance of 12 cm from the optical center, which is less than the focal length of the lens. Therefore, the image formed is real and inverted.<\/p>\n
The distance between the object and the image is given by the formula:<\/p>\n
$$d_o + d_i = f$$<\/p>\n
where $d_o$ is the distance of the object from the lens, $d_i$ is the distance of the image from the lens, and $f$ is the focal length of the lens.<\/p>\n
In this case, we know that $d_o = 12 \\text{ cm}$ and $d_i = 25 \\text{ cm}$. Substituting these values into the formula, we get:<\/p>\n
$$12 \\text{ cm} + 25 \\text{ cm} = f$$<\/p>\n
$$f = 37 \\text{ cm}$$<\/p>\n
The power of the lens is then given by:<\/p>\n
$$P = \\frac{1}{f} = \\frac{1}{37 \\text{ cm}} = -0.027 \\text{ m}^{-1} = -4.33 \\text{ diopters}$$<\/p>\n
Therefore, the power of the convex lens is $\\boxed{\\text{A. }-4.33 \\text{ diopters}}$.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”-4.33 diopters” option2=”12.33 diopters” option3=”-12.33 diopters” option4=”4.33 diopters” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[25],"tags":[],"class_list":["post-22894","post","type-post","status-publish","format-standard","hentry","category-physics","no-featured-image-padding"],"yoast_head":"\n