{"id":21757,"date":"2024-04-15T06:10:38","date_gmt":"2024-04-15T06:10:38","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=21757"},"modified":"2024-04-15T06:10:38","modified_gmt":"2024-04-15T06:10:38","slug":"railway-tracks-are-banked-on-curves-a-necessary-centrifugal-force-may-be-obtained-from-the-horizontal-component-weight-of-the-train-b-to-avoid-frictional-force-between-the-tracks-and-wheels-c-neces","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/railway-tracks-are-banked-on-curves-a-necessary-centrifugal-force-may-be-obtained-from-the-horizontal-component-weight-of-the-train-b-to-avoid-frictional-force-between-the-tracks-and-wheels-c-neces\/","title":{"rendered":"Railway tracks are banked on curves A. necessary centrifugal force may be obtained from the horizontal component weight of the train B. to avoid frictional force between the tracks and wheels C. necessary centripetal force may be obtained from the horizontal component of the weight of the train D. the train may not fly off in the opposite direction"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a99c5988fc39\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    necessary centrifugal force may be obtained from the horizontal component weight of the train                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"false\">\r\n                    to avoid frictional force between the tracks and wheels                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"true\">\r\n                    necessary centripetal force may be obtained from the horizontal component of the weight of the train                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    the train may not fly off in the opposite direction                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is: C. necessary centripetal force may be obtained from the horizontal component of the weight of the train.<\/p>\n<p>When a train goes around a curve, it experiences a centripetal force that pulls it towards the center of the curve. This force is provided by the friction between the wheels and the tracks. However, if the curve is too sharp, the frictional force may not be enough to keep the train from derailing. In this case, the tracks can be banked, or tilted, so that the horizontal component of the train&#8217;s weight <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> provides some of the centripetal force. This reduces the <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> amount of frictional force required, and makes it safer for the train to travel around the curve.<\/p>\n<p>Option A is incorrect because the horizontal component of the train&#8217;s weight is not enough to provide the necessary centripetal force for a sharp curve. Option B is incorrect because frictional force is still required to keep the train from derailing, even on banked tracks. Option D is incorrect because the train is not in danger of flying off in the opposite direction.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[25],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Railway tracks are banked on curves A. necessary centrifugal force may be obtained from the horizontal component weight of the train B. to avoid frictional force between the tracks and wheels C. necessary centripetal force may be obtained from the horizontal component of the weight of the train D. the train may not fly off in the opposite direction<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, 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