[amp_mcq option1=”0.14 m\/s” option2=”140 m\/s” option3=”1.4 km\/s” option4=”14 m\/s” correct=”option4″]<\/p>\n
The correct answer is D. 14 m\/s.<\/p>\n
The maximum velocity for the overturn of a car moving on a circular track of radius 100 m is given by the following formula:<\/p>\n
$$v_c = \\sqrt{\\frac{rg}{\\mu}}$$<\/p>\n
where $r$ is the radius of the track, $g$ is the acceleration due to gravity, and $\\mu$ is the coefficient of friction between the road and tyre.<\/p>\n
In this case, $r = 100$ m, $g = 9.8 \\frac{m}{s^2}$, and $\\mu = 0.2$. Substituting these values into the formula, we get:<\/p>\n
$$v_c = \\sqrt{\\frac{(100 \\text{ m})(9.8 \\frac{m}{s^2})}{0.2}} = 14 \\text{ m\/s}$$<\/p>\n
Option A is incorrect because it is too small. Option B is incorrect because it is too large. Option C is incorrect because it is a unit of speed, not a velocity.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”0.14 m\/s” option2=”140 m\/s” option3=”1.4 km\/s” option4=”14 m\/s” correct=”option4″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[25],"tags":[],"class_list":["post-21736","post","type-post","status-publish","format-standard","hentry","category-physics","no-featured-image-padding"],"yoast_head":"\n