[amp_mcq option1=”$$\\frac{1}{8}$$” option2=”$$\\frac{1}{2}$$” option3=”$$\\frac{3}{8}$$” option4=”$$\\frac{3}{4}$$” correct=”option1″]<\/p>\n
The probability of getting exactly two heads in three tosses is $\\frac{3}{8}$.<\/p>\n
To get exactly two heads, the first toss must be a head, and the second and third tosses must be either both heads or both tails. The probability of the first toss being a head is $\\frac{1}{2}$. The probability of the second and third tosses being both heads is $\\frac{1}{2} \\cdot \\frac{1}{2} = \\frac{1}{4}$. The probability of the second and third tosses being both tails is also $\\frac{1}{4}$. Therefore, the probability of getting exactly two heads in three tosses is $\\frac{1}{2} \\cdot \\frac{1}{4} + \\frac{1}{2} \\cdot \\frac{1}{4} = \\frac{3}{8}$.<\/p>\n
Option A is incorrect because it is the probability of getting exactly one head in three tosses. Option B is incorrect because it is the probability of getting at least one head in three tosses. Option C is incorrect because it is the probability of getting two heads in three tosses, regardless of whether the first toss is a head or a tail. Option D is incorrect because it is the probability of getting three heads in three tosses.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”$$\\frac{1}{8}$$” option2=”$$\\frac{1}{2}$$” option3=”$$\\frac{3}{8}$$” option4=”$$\\frac{3}{4}$$” correct=”option1″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[691],"tags":[],"class_list":["post-20316","post","type-post","status-publish","format-standard","hentry","category-probability-and-statistics","no-featured-image-padding"],"yoast_head":"\n