{"id":20294,"date":"2024-04-15T05:50:58","date_gmt":"2024-04-15T05:50:58","guid":{"rendered":"https:\/\/exam.pscnotes.com\/mcq\/?p=20294"},"modified":"2024-04-15T05:50:58","modified_gmt":"2024-04-15T05:50:58","slug":"a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode","status":"publish","type":"post","link":"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/","title":{"rendered":"A probability distribution with right skew is shown in the figure. The correct statement for the probability distribution is A. Mean is equal to mode B. Mean is greater than median but less than mode C. Mean is greater than median and mode D. Mode is greater than median"},"content":{"rendered":"<p>\r\n    <!-- Check if it's an AMP page -->\r\n            <!-- Non-AMP version -->\r\n        <div class=\"mcq-container\" data-quiz-id=\"quizState_6a992a26e2d58\">\r\n                                            <div class=\"option\" data-option-key=\"option1\" data-is-correct=\"false\">\r\n                    Mean is equal to mode                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option2\" data-is-correct=\"true\">\r\n                    Mean is greater than median but less than mode                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option3\" data-is-correct=\"false\">\r\n                    Mean is greater than median and mode                <\/div>\r\n                                            <div class=\"option\" data-option-key=\"option4\" data-is-correct=\"false\">\r\n                    Mode is greater than median                <\/div>\r\n                            \r\n            <!-- Feedback messages for non-AMP -->\r\n            <div class=\"feedback\" data-feedback=\"wrong\">Answer is Right!<\/div>\r\n            <div class=\"feedback\" data-feedback=\"right\">Answer is Wrong!<\/div>\r\n        <\/div>\r\n\r\n        <script>\r\n        document.addEventListener('DOMContentLoaded', function () {\r\n            var containers = document.querySelectorAll('.mcq-container');\r\n\r\n            containers.forEach(function(container) {\r\n                var options = container.querySelectorAll('.option');\r\n                var feedbackSelect = container.querySelector('[data-feedback=\"select\"]');\r\n                var feedbackWrong = container.querySelector('[data-feedback=\"wrong\"]');\r\n                var feedbackRight = container.querySelector('[data-feedback=\"right\"]');\r\n\r\n                options.forEach(function(option) {\r\n                    option.addEventListener('click', function() {\r\n                        var selectedOption = option.getAttribute('data-option-key');\r\n                        var isCorrect = option.getAttribute('data-is-correct') === 'true';\r\n\r\n                        \/\/ Remove previous selections\r\n                        options.forEach(function(opt) {\r\n                            opt.classList.remove('correct', 'incorrect');\r\n                        });\r\n\r\n                        \/\/ Add the correct\/incorrect class\r\n                        if (isCorrect) {\r\n                            option.classList.add('correct');\r\n                            feedbackRight.hidden = false;\r\n                            feedbackWrong.hidden = true;\r\n                        } else {\r\n                            option.classList.add('incorrect');\r\n                            feedbackRight.hidden = true;\r\n                            feedbackWrong.hidden = false;\r\n                        }\r\n\r\n                        \/\/ Hide select feedback\r\n                        feedbackSelect.hidden = true;\r\n                    });\r\n                });\r\n            });\r\n        });\r\n        <\/script>\r\n    \r\n    <!--more--><\/p>\n<p>The correct answer is B. Mean is greater than median but less than mode.<\/p>\n<p>A probability distribution with right skew is one in which the tail on the right side of the distribution is longer than the tail on the left <div class=\"telegram-channel-container\">\r\n        <a href=\"https:\/\/t.me\/pscnotes2025\" target=\"_blank\" class=\"telegram-channel-button\">\r\n            <span class=\"telegram-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 496 512\">\r\n                    <path fill=\"white\" d=\"M248,8C111,8,0,119,0,256s111,248,248,248s248-111,248-248S385,8,248,8z M362,177L320,367c-3,14-10,18-20,14l-56-41l-27,26 c-3,3-5,5-10,5l4-63L323,196c5-5-1-7-8-3l-98,62l-42-13c-9-3-10-9,2-14l162-63C351,160,365,164,362,177z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Join Our Telegram Channel\r\n        <\/a>\r\n    <\/div> side. This means that there are more data points with values that are greater than the mean than there are data points with values that are less than the mean.<\/p>\n<p>The mode is the value that occurs most often in a data set. The median is the value that divides the data set into two equal parts, with half of the data points below the median and half of the data points above the median.<\/p>\n<p>In a right-skew distribution, the mode is typically less than the median, which <div class=\"youtube-subscribe-container\">\r\n        <a href=\"https:\/\/www.youtube.com\/channel\/UCNHT8lW-JmLC68rjBfZhdkg?sub_confirmation=1\" target=\"_blank\" class=\"youtube-subscribe-button\">\r\n            <span class=\"youtube-icon\">\r\n                <svg xmlns=\"http:\/\/www.w3.org\/2000\/svg\" viewBox=\"0 0 576 512\">\r\n                    <path d=\"M549.7 124.1c-6.3-23.7-24.8-42.3-48.3-48.6C458.8 64 288 64 288 64S117.2 64 74.6 75.5c-23.5 6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z\"\/>\r\n                <\/svg>\r\n            <\/span>\r\n            Subscribe on YouTube\r\n        <\/a>\r\n    <\/div> is typically less than the mean. This is because the tail on the right side of the distribution contains more data points that are greater than the mean, which pulls the mean up.<\/p>\n<p>Here is a diagram that illustrates a right-skew distribution:<\/p>\n<p>As you can see, the mode is the lowest value, the median is the middle value, and the mean is the highest value.<\/p>\n<p>Therefore, the correct statement for the probability distribution is B. Mean is greater than median but less than mode.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Join Our Telegram Channel Subscribe on YouTube<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[691],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v22.2 (Yoast SEO v23.3) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>A probability distribution with right skew is shown in the figure. The correct statement for the probability distribution is A. Mean is equal to mode B. Mean is greater than median but less than mode C. Mean is greater than median and mode D. Mode is greater than median<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"A probability distribution with right skew is shown in the figure. The correct statement for the probability distribution is A. Mean is equal to mode B. Mean is greater than median but less than mode C. Mean is greater than median and mode D. Mode is greater than median\" \/>\n<meta property=\"og:description\" content=\"Join Our Telegram Channel Subscribe on YouTube\" \/>\n<meta property=\"og:url\" content=\"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/\" \/>\n<meta property=\"og:site_name\" content=\"MCQ and Quiz for Exams\" \/>\n<meta property=\"article:published_time\" content=\"2024-04-15T05:50:58+00:00\" \/>\n<meta name=\"author\" content=\"rawan239\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"rawan239\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"A probability distribution with right skew is shown in the figure. The correct statement for the probability distribution is A. Mean is equal to mode B. Mean is greater than median but less than mode C. Mean is greater than median and mode D. Mode is greater than median","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/","og_locale":"en_US","og_type":"article","og_title":"A probability distribution with right skew is shown in the figure. The correct statement for the probability distribution is A. Mean is equal to mode B. Mean is greater than median but less than mode C. Mean is greater than median and mode D. Mode is greater than median","og_description":"Join Our Telegram Channel Subscribe on YouTube","og_url":"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/","og_site_name":"MCQ and Quiz for Exams","article_published_time":"2024-04-15T05:50:58+00:00","author":"rawan239","twitter_card":"summary_large_image","twitter_misc":{"Written by":"rawan239","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/","url":"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/","name":"A probability distribution with right skew is shown in the figure. The correct statement for the probability distribution is A. Mean is equal to mode B. Mean is greater than median but less than mode C. Mean is greater than median and mode D. Mode is greater than median","isPartOf":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#website"},"datePublished":"2024-04-15T05:50:58+00:00","dateModified":"2024-04-15T05:50:58+00:00","author":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209"},"breadcrumb":{"@id":"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/exam.pscnotes.com\/mcq\/a-probability-distribution-with-right-skew-is-shown-in-the-figure-the-correct-statement-for-the-probability-distribution-is-a-mean-is-equal-to-mode-b-mean-is-greater-than-median-but-less-than-mode\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/exam.pscnotes.com\/mcq\/"},{"@type":"ListItem","position":2,"name":"mcq","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/"},{"@type":"ListItem","position":3,"name":"Engineering maths","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/engineering-maths\/"},{"@type":"ListItem","position":4,"name":"Probability and statistics","item":"https:\/\/exam.pscnotes.com\/mcq\/category\/mcq\/engineering-maths\/probability-and-statistics\/"},{"@type":"ListItem","position":5,"name":"A probability distribution with right skew is shown in the figure. The correct statement for the probability distribution is A. Mean is equal to mode B. Mean is greater than median but less than mode C. Mean is greater than median and mode D. Mode is greater than median"}]},{"@type":"WebSite","@id":"https:\/\/exam.pscnotes.com\/mcq\/#website","url":"https:\/\/exam.pscnotes.com\/mcq\/","name":"MCQ and Quiz for Exams","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/exam.pscnotes.com\/mcq\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/5807dafeb27d2ec82344d6cbd6c3d209","name":"rawan239","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/exam.pscnotes.com\/mcq\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/d97f17072bfa490596c8f78363955d55?s=96&d=mm&r=g","caption":"rawan239"},"sameAs":["https:\/\/exam.pscnotes.com"],"url":"https:\/\/exam.pscnotes.com\/mcq\/author\/rawan239\/"}]}},"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/20294"}],"collection":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/comments?post=20294"}],"version-history":[{"count":0,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/posts\/20294\/revisions"}],"wp:attachment":[{"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/media?parent=20294"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/categories?post=20294"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/exam.pscnotes.com\/mcq\/wp-json\/wp\/v2\/tags?post=20294"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}