[amp_mcq option1=”$$\\frac{1}{5}$$” option2=”$$\\frac{1}{{25}}$$” option3=”$$\\frac{{20}}{{99}}$$” option4=”$$\\frac{{19}}{{495}}$$” correct=”option3″]<\/p>\n
The probability of event A happening, then event B, is the probability of event A happening times the probability of event B happening given that event A already happened. In this case, event A is selecting one defective item and event B is selecting another defective item.<\/p>\n
The probability of selecting one defective item is the number of defective items divided by the total number of items, $\\frac{20}{100}$.<\/p>\n
The probability of selecting another defective item after one defective item has already been selected is the number of defective items remaining divided by the total number of items remaining, $\\frac{19}{99}$.<\/p>\n
Therefore, the probability of selecting two defective items at random without replacement is $\\frac{20}{100} \\cdot \\frac{19}{99} = \\boxed{\\frac{19}{495}}$.<\/p>\n
Option A is incorrect because it is the probability of selecting one defective item. Option B is incorrect because it is the probability of selecting two defective items with replacement. Option C is incorrect because it is the probability of selecting one defective item and one non-defective item.<\/p>\n","protected":false},"excerpt":{"rendered":"
[amp_mcq option1=”$$\\frac{1}{5}$$” option2=”$$\\frac{1}{{25}}$$” option3=”$$\\frac{{20}}{{99}}$$” option4=”$$\\frac{{19}}{{495}}$$” correct=”option3″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[691],"tags":[],"class_list":["post-20289","post","type-post","status-publish","format-standard","hentry","category-probability-and-statistics","no-featured-image-padding"],"yoast_head":"\n