[amp_mcq option1=”The function \\[\\sqrt[{\\text{x}}]{{\\text{x}}}\\],(x > 0), has the global minima at x = e” option2=”The function \\[\\sqrt[{\\text{x}}]{{\\text{x}}}\\],(x > 0), has the global maxima at x = e” option3=”The function x3 has neither global minima nor global maxima” option4=”The function |x| has the global minima at x = 0″ correct=”option2″]<\/p>\n
The correct answer is: B. The function $\\sqrt[{\\text{x}}]{{\\text{x}}}$,(x > 0), has the global maxima at x = e<\/strong><\/p>\n The function $\\sqrt[{\\text{x}}]{{\\text{x}}}$,(x > 0), is a decreasing function. This means that for any two values $x_1$ and $x_2$ such that $x_1 > x_2$, we have $\\sqrt[{\\text{x}}]{{\\text{x}}}(x_1) < \\sqrt[{\\text{x}}]{{\\text{x}}}(x_2)$. In particular, this means that $\\sqrt[{\\text{x}}]{{\\text{x}}}$ has no global maxima, since there is no value $x$ such that $\\sqrt[{\\text{x}}]{{\\text{x}}}(x) > \\sqrt[{\\text{x}}]{{\\text{x}}}(y)$ for all $y$.<\/p>\n The other options are all correct. The function $x^3$ has a global minimum at $x=0$, since $x^3(0)=0$ and $x^3(x)>0$ for all $x>0$. The function $|x|$ has no global minima or global maxima, since it is a non-decreasing function.<\/p>\n","protected":false},"excerpt":{"rendered":" [amp_mcq option1=”The function \\[\\sqrt[{\\text{x}}]{{\\text{x}}}\\],(x > 0), has the global minima at x = e” option2=”The function \\[\\sqrt[{\\text{x}}]{{\\text{x}}}\\],(x > 0), has the global maxima at x = e” option3=”The function x3 has neither global minima nor global maxima” option4=”The function |x| has the global minima at x = 0″ correct=”option2″]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[690],"tags":[],"class_list":["post-20246","post","type-post","status-publish","format-standard","hentry","category-calculus","no-featured-image-padding"],"yoast_head":"\n